A. 53.33
B. 54.68
C. 55
D. None of these
Required average = (55 x 50 + 60 x 55 + 45 x 60) / (55 + 60 + 45)
= (2750 + 3300 + 2700) /160
= 54.68 is correct Answer
A. 53.33
B. 54.68
C. 55
D. None of these
Required average = (55 x 50 + 60 x 55 + 45 x 60) / (55 + 60 + 45)
= (2750 + 3300 + 2700) /160
= 54.68 is correct Answer
A. 17 kg
B. 20 kg
C. 26 kg
D. 31 kg
Let A, B, C represent their respective weights. Then, we have: A + B + C = (45 x 3) = 135 …. (i) A + B = (40 x 2) = 80 …. (ii) B + C = (43 x 2) = 86 ….(iii) Adding (ii) and (iii), we get: A + 2B + C = 166 …. (iv) Subtracting (i) from (iv), we get : B = 31. B’s weight = 31 kg
A. 123
B. 137
C. 121
D. 122
Sum of 18 observations = 18×124 =2232
Correct sum of 18 observations = 2232-46-82+64+28
= 2196
Therefore, Correct average =2196/18 = 122
A. 36km/h
B. 45km/h
C. 48km/h
D. 50km/h
Explanation:
Speed of person from x to y =40 km/h
Speed of person from y to x =(40×150)/100 = 60km/h
Since the distance travelled is same
Therefore, Average Speed = (2x40x60)/40+60 = 48km/h
A. 57.4
B. 57.5
C. 58.9
D. 59.1
Correct mean = 30x 58.5 -57 +75/30
= 1755+18/30 = 1773/30 = 59.1
A. 16
B. 12
C. 8
D. 6
Let the number of women workers be x
According to the question 22*x+16*8 = 15(16+x)
=> 22x+128 =240 +15x
=> 22x-15x = 240 -128
=> 7x=112
Therefore, x=112/7 =16
Therefore, Unmarried women workers =(16-10) = 6
A. 1:2
B. 2:3
C. 3:4
D. 3:5
Let the ratio be k : 1. Then,
k * 16.4 + 1 * 15.4 = (k + 1) * 15.8
= (16.4 – 15.8)k = (15.8 – 15.4)
= k = 0.4/0.6 = 2/3
Required ratio = 2/3 : 1 = 2:3
A. 8
B. 9
C. 10
D. 11
Let the number of papers be x. Then,
63x + 20 + 2 = 65x
= 2x = 22
= x = 11
A. 20
B. 21
C. 22
D. 23
Explanation:
Let the total number of workers be x. Then,
8000x = (12000 * 7) + 6000(x – 7)
= 2000x = 42000
= x = 21
A. 45
B. 50
C. 51.4 approx.
D. 54.6 approx.
Explanation:
Let the required means score be x. Then,
20 * 80 + 25 * 31 + 55 * x = 52 * 100
= 1600 + 775 + 55x = 5200
= 55x = 2825
= x = 565/11 = 51.4.