## Express 1.09 in term of Percentage.

Express 1.09 in term of Percentage.

A. 1.09%
B. 10.9%
C. 109%
D. None of these

## Calculate the Average of 1,2,3,4,5.

Calculate the Average of 1,2,3,4,5.

A. 1
B. 2
C. 3
D. 4

## Find the Missing Number in the series 1, 6, 13, 22, 33 ?

Find the Missing Number in the series 1, 6, 13, 22, 33 ?

A. 36
B. 40
C. 46
D. 52

## Today is khadija’s birthday. After one year, she will become two times as she was ten years ago. current age of Khadija?

Today is khadija’s birthday. After one year, she will become two times as she was ten years ago. current age of Khadija?

A. 19
B. 20
C. 21
D. 22

let her age be x
after 1 year her age will be x+1=2(x-10)
x+1=2x-20
1+20=2x-x
x=21 years

## If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, then the average marks of all the students is__________?

If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, then the average marks of all the students is__________?

A. 53.33
B. 54.68
C. 55
D. None of these
Required average = (55 x 50 + 60 x 55 + 45 x 60) / (55 + 60 + 45)
= (2750 + 3300 + 2700) /160

## The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is___________?

The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is___________?

A. 17 kg
B. 20 kg
C. 26 kg
D. 31 kg
Let A, B, C represent their respective weights. Then, we have: A + B + C = (45 x 3) = 135 …. (i) A + B = (40 x 2) = 80 …. (ii) B + C = (43 x 2) = 86 ….(iii) Adding (ii) and (iii), we get: A + 2B + C = 166 …. (iv) Subtracting (i) from (iv), we get : B = 31. B’s weight = 31 kg

## The average of 18 observations was calculated and it was 124. Later on it was discovered that two observations 46 and 82 were incorrect. The correct values are 64 and 28. The correct average of 18 observations is___________?

The average of 18 observations was calculated and it was 124. Later on it was discovered that two observations 46 and 82 were incorrect. The correct values are 64 and 28. The correct average of 18 observations is___________?

A. 123
B. 137
C. 121
D. 122
Sum of 18 observations = 18×124 =2232
Correct sum of 18 observations = 2232-46-82+64+28
= 2196
Therefore, Correct average =2196/18 = 122

## A person travels from x to y at a speed of 40Km/h and returns by increasing his speed 50%. What is his average speed for both the trips?

A person travels from x to y at a speed of 40Km/h and returns by increasing his speed 50%. What is his average speed for both the trips?

A. 36km/h
B. 45km/h
C. 48km/h
D. 50km/h
Explanation:
Speed of person from x to y =40 km/h
Speed of person from y to x =(40×150)/100 = 60km/h
Since the distance travelled is same
Therefore, Average Speed = (2x40x60)/40+60 = 48km/h

## The mean marks of 30 students in a class is 58.5. Later on it was found that 75 was wrongly recorded as 57. Find the correct them.

The mean marks of 30 students in a class is 58.5. Later on it was found that 75 was wrongly recorded as 57. Find the correct them.

A. 57.4
B. 57.5
C. 58.9
D. 59.1
Correct mean = 30x 58.5 -57 +75/30
= 1755+18/30 = 1773/30 = 59.1

## The average of women and child workers in a factory was 15%yr. The average age of all the 16 children was 8yr and average age of women workers was 22 yrs if ten women workers were married then the number of unmarried women workers were________?

The average of women and child workers in a factory was 15%yr. The average age of all the 16 children was 8yr and average age of women workers was 22 yrs if ten women workers were married then the number of unmarried women workers were________?

A. 16
B. 12
C. 8
D. 6
Let the number of women workers be x
According to the question 22*x+16*8 = 15(16+x)
=> 22x+128 =240 +15x
=> 22x-15x = 240 -128
=> 7x=112
Therefore, x=112/7 =16
Therefore, Unmarried women workers =(16-10) = 6