Find the greatest number of four digits which when divided by 10, 15, 21 and 28 leaves 4, 9, 15 and 22 as remainders respectively?
A. 9654
B. 9666
C. 9664
D. 9864
A. 9654
B. 9666
C. 9664
D. 9864
A. 58
B. 86
C. 49
D. None of these
Let the four integers be A, B, C and D where A > B > C > D.
(A + B + C + D)/4 = 69 => A + B + C + D = 276 —> (1)
A = 93, D = 39 and B – C = 28
(1) => B + C = 276 – (A + D) = 276 – 132 = 144.
B + B -28 = 144
B = (144 + 28)/2 = 86
A. Rs. 992
B. Rs. 1112
C. Rs. 1056
D. Rs. 1182
Principal = 800 SI = 120 Time = 3 year
Rate = (100*120/800*3) = 5%
New rate = 8 % principal = 800 time 3 year
SI = (800*8*3/100) = 192
New amount = 800 + 192= 992
A. 2:5
B. 1:5
C. 3:5
D. 4:5
A. 12 days
B. 5 days
C. 9 days
D. 6 days
A. 9.8
B. 10
C. 10.5
D. 10.8
A. 1160
B. 1100
C. 1080
D. 1210
E. None of these
Explanation:
Number of sweets each child got = 15% of 80 = 15/100 * 80 = 12.
Number of sweets 80 children got = 80 * 12 = 960.
Number of sweets each youngster got = 25% of 80 = 25/100 * 80 = 20.
Number of sweets 10 youngsters got = 10 * 20 = 200.
Total number of sweets = 960 + 200 = 1160.