The average of five numbers is 27. If one number is excluded, the average becomes 25. The excluded number is__________?

Byadmin July 10, 2019August 4, 2021

The average of five numbers is 27. If one number is excluded, the average becomes 25. The excluded number is__________?

A. 25
B. 27
C. 30
D. 35
Explanation:
Excluded number = (27 * 5) – (25 * 4) = 135 – 100 = 35.

interest Mcqs | Mathematics Mcqs

A sum of money amounts to Rs 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is :

A sum of money amounts to Rs 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is :

A. 5%
B. 8%
C. 12%
D. 15%
S.I. for 3 years = Rs. (12005 – 9800) = Rs. 2205. S.I. for 5 years = Rs. ( 2205/3 X 5 ) = Rs. 3675. So Principal = Rs. (9800 – 3675) = Rs. 6125. Hence, rate = ( 100 X 3675/6125 X 5 X 5 )% = 12%.

Read More A sum of money amounts to Rs 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is :
Areas | Mathematics Mcqs

The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is__________?

The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is__________?

A. 1520 m2
B. 2420 m2
C. 2480 m2
D. 2520 m2

Read More The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is__________?
Areas | Mathematics Mcqs

How many meters of carpet 63cm will be required to be a floor of a room 14m by 9cm?

How many meters of carpet 63cm will be required to be a floor of a room 14m by 9cm?

A. 200m
B. 210m
C. 220m
D. 185m

Read More How many meters of carpet 63cm will be required to be a floor of a room 14m by 9cm?
Mathematics Mcqs | Problems on L.C.M and H.C.F

A wholesale tea dealer 408 kilograms, 468 kilograms and 516 kilograms of three different qualities of tea. He wants it all to be packed into boxes of equal size without mixing. Find the capacity of the largest possible box?

A wholesale tea dealer 408 kilograms, 468 kilograms and 516 kilograms of three different qualities of tea. He wants it all to be packed into boxes of equal size without mixing. Find the capacity of the largest possible box?

A. 50
B. 36
C. 24
D. 12
Explanation:
HCF of 408, 468, 516 = 12

Read More A wholesale tea dealer 408 kilograms, 468 kilograms and 516 kilograms of three different qualities of tea. He wants it all to be packed into boxes of equal size without mixing. Find the capacity of the largest possible box?
Arithmetic Mcqs | Average Mcqs | Basic Maths Mcqs | Mathematics Mcqs

The average of runs of a cricket player of 10 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4?

The average of runs of a cricket player of 10 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4?

A. 2
B. 4
C. 70
D. 76
Explanation:
Average after 11 innings = 36
Required number of runs
= (36 * 11) – (32 * 10) = 396 – 320 = 76

Read More The average of runs of a cricket player of 10 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4?
Basic Maths Mcqs | Mathematics Mcqs | Time and Work Mcqs

X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last ?

X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last ?

A. 6 days
B. 10 days
C. 15 days
D. 20 days
Work done by X in 4 days = ( 1/20X 4 ) = 1/5 Remaining work = (1 – 1/5 ) = 4/5 (X + Y)’s 1 day’s work = 1/20 + 1/12 = 8/60 = 2/15 Now, 2/15 work is done by X and Y in 1 day. So, 4/5 work will be done by X and Y in 15/2 X 4/5 = 6 days Hence, total time taken = (6 + 4) days = 10 days.

Read More X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last ?

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