The average age of M boys is ‘b’ years and of ‘n’ girls ‘c’ years. The average age of all together is_________?
A. (mb – nc)/ (m + n) years
B. (mb + nc)/ (m – n) years
C. (mb + nc)/ (m + n) years
D. (mb – nc)/ (m – n) years
A. (mb – nc)/ (m + n) years
B. (mb + nc)/ (m – n) years
C. (mb + nc)/ (m + n) years
D. (mb – nc)/ (m – n) years
A. Rs 9000.30
B. Rs 9720
C. Rs 10123.20
D. Rs 10483.20
E. None of these
Explanation:
C.I = [25000 × (1+12/100)3-25000]
= Rs [(25000 × 28/25 × 28/25 × 28/25)-25000]
=Rs(175616/5-25000) = Rs (35123.20 – 25000)
= Rs 10123.20
A. 216
B. 243
C. 215
D. 729
Explanation:
Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 * 6 * 6 = 216. Of these attempts, one of them is a successful attempt.
Maximum number of unsuccessful attempts = 216 – 1 = 215.
A. Rs. 300
B. Rs. 400
C. Rs. 500
D. Rs. 600
E. None of these
Explanation:
Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6
And also given that, profit of B is Rs. 1500
=> 5 parts out of 15 parts is Rs. 1500
Now, required difference is 6 – 4 = 2 parts
Required difference = 2/5 (1500) = Rs. 600
A. 100 %
B. 200 %
C. 700 %
D. 800 %
A. Rs. 1325
B. Rs. 1300
C. Rs. 1350
D. Rs. 1500
A. 2 : 5
B. 1 : 5
C. 3 : 5
D. 4 : 5
The volume of the cone = (1/3)πr2h
Only radius (r) and height (h) are varying.
Hence, (1/3)π may be ignored.
V1/V2 = r12h1/r22h2 => 1/10 = (1)2h1/(2)2h2
=> h1/h2 = 2/5
i.e. h1 : h2 = 2 : 5