In a rhombus whose area is 144 sq.cm on of its diagonals is twice as long as the other. The lengths of its diagonals are:_________?
		A. 24 cm,48cm
B. 12cm,24cm
C. 6√2cm,12√2cm
D. 6cm,12cm
		A. 24 cm,48cm
B. 12cm,24cm
C. 6√2cm,12√2cm
D. 6cm,12cm
		A. 1
B. 2
C. 3
D. 4
Explanation:
Let the numbers be 13a and 13b.
Then, 13a * 13b = 2028 => ab = 12.
Now, co-primes with product 12 are (1, 12) and (3, 4).
So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).
Clearly, there are 2 such pairs.
		A. 30 Years
B. 31 years
C. 26 years
D. 33 years
Explanation:
Total age seven persons = (28 * 7)years
Total age of the first three persons and the last three persons are (21 * 3) years and (34 * 3) years respectively.
Age of the person sitting in the middle of the row = 28 * 7 – 21 * 3 – 34 * 3 = 196 – 63 – 102 = 31 years
		A. 5
B. 6
C. 7
D. 8
Relative speed = Speed of A + Speed of B (∴ they walk in opposite directions)
= 2 + 3 = 5 rounds per hour
=> They cross each other 5 times in 1 hour and 2 times in 1/2 hour
Time duration from 8 am to 9.30 am = 1.5 hour
Hence they cross each other 7 times before 9.30 am
		A. 248
B. 240
C. 228
D. 236
E. None of these
Explanation:
Let the five consecutive even numbers be 2(x – 2), 2(x – 1), 2x, 2(x + 1) and 2(x + 2)
Their sum = 10x = 440
x = 44 => 2(x – 2) = 84
Second least number of the other set = 2(84) – 121 = 47
This set has its least number as 46.
Sum of the numbers of this set = 46 + 47 + 48 + 49 + 50
= 48 – 2 + 48 – 1 + 48 + 48 + 1 + 48 + 2 => 5(48) = 240
		A. 5 m
B. 7 m
C. 8 m
D. 44 m
		A. 12
B. 48
C. 84
D. 108
Explanation:
Let the numbers be x and 4x. Then, x * 4x = 84 * 21 x2 = (84 * 21)/4 = x = 21.
Hence, larger number = 4x = 84.