If the length of diagonal AC of a square ABCD is 5.2 cm then area of the square ABCD is_________?
		A. 15.12 sq.cm
B. 13.52 sq.cm
C. 12.62 sq.cm
D. 10 sq.cm
		A. 15.12 sq.cm
B. 13.52 sq.cm
C. 12.62 sq.cm
D. 10 sq.cm
		A. 80%
B. 20%
C. 40%
D. 50%
E. None of these
Explanation:
Number of students passed = 60% of 140 = 60/100 * 140 = 84
Number of students failed = 140 – 84 = 56.
Required percentage = 28/56 * 100 = 50%.
		A. Rs. 21000
B. Rs. 17500
C. Rs. 19000
D. Rs. 24500
Let the cost prices of the colour television sold at 30% profit and 40% profit be Rs. x and Rs. (35000 – x) respectively.
Total selling price of televisions = x + 30/100 x + (35000 – x) + 40/100 (35000 – x)
=> 130/100 x + 140/100 (35000 – x) = 35000 + 32/100 (35000)
x = 28000
35000 – x = 7000
Difference in the cost prices of televisions = Rs. 21000
		A. 3
B. 9
C. 12
D. 15
Explanation:
Average = 3(1 + 2 + 3 + 4 + 5)/5 = 45/5 = 9
		A. 30 days
B. 25 days
C. 20 days
D. 15 days
Work done by P and Q in 1 day = 1/10
Work done by R in 1 day = 1/50
Work done by P, Q and R in 1 day = 1/10 + 1/50 = 6/50
But Work done by P in 1 day = Work done by Q and R in 1 day . Hence the above equation can be written as
Work done by P in 1 day × 2 = 6/50
=> Work done by P in 1 day = 3/50
=> Work done by Q and R in 1 day = 3/50
Hence work done by Q in 1 day = 3/50 – 1/50 = 2/50 = 1/25
So Q alone can do the work in 25 days
		A. 3/2 cm
B. 1/2 cm
C. 3/4 cm
D. 3 cm
		A. 35%
B. 38%
C. 32%
D. 29%
E. None of these
Explanation:
Let the CP of an article be Rs. 100
Given that successive discounts are 20% and 15%.
SP = 85% of 80% of 100 = (85/100)(80/100)(100)
=> SP = Rs. 68
Clearly, single discount is 32%.