Find the average of all the numbers between 6 and 34 which are divisible by 5.
A. 18
B. 20
C. 24
D. 30
Explanation:
Average = (10 + 15 + 20 + 25 + 30)/5 = 100/5 = 20
A. 18
B. 20
C. 24
D. 30
Explanation:
Average = (10 + 15 + 20 + 25 + 30)/5 = 100/5 = 20
A. 1 : 96
B. 1 : 48
C. 1 : 84
D. 1 : 68
Let the length and the breadth of the rectangle be 4x cm and 3x respectively.
(4x)(3x) = 6912
12×2 = 6912
x2 = 576 = 4 * 144 = 22 * 122 (x > 0)
=> x = 2 * 12 = 24
Ratio of the breadth and the areas = 3x : 12×2 = 1 : 4x = 1: 96.
A. 6 hrs 21 min
B. 6 hrs 24 min
C. 6 hrs 27 min
D. 6 hrs 30 min
Time taken to cover 600 km = ( 600/100 ) hrs = 6 hrs. Number of stoppages = ( 600/75 – 1 ) = 7 Total time of stoppage = (3 x 7) min = 21 min. Hence, total time taken = 6 hrs 21 min.
A. 65 years
B. 56 years
C. 45 years
D. 57 years
Simple interest is given by the formula SI = (pnr/100), where p is the principal, n is the numberof years for which it is invested, r is the rate of interest per annum
In this case, Rs. 1250 has become Rs.10,000.
Therefore, the interest earned = 10,000 – 1250 = 8750.
8750 = [(1250 x n x 12.5)/100]
=> n = 700 / 12.5 = 56 years.
A. 20
B. 25
C. 125
D. 60
M1*D1*W2 = M2*D2*W1
Where, M – number of people working
D – time of work
W – number of tasks or work
6*4*W2 = 10*6*50
W2 = 125 tasks
A. 300 sq m
B. 250 sq m
C. 200 sq m
D. 400 sq m
A. 29
B. 32
C. 55
D. 30
We know that, the number of straight lines that can be formed by the 11 points in which 6 points are collinear and no other set of three points, except those that can be selected out of these 6 points are collinear.
Hence, the required number of straight lines
= ¹¹C₂ – ⁶C₂ – ⁵C₂ + 1 + 1
= 55 – 15 – 10 + 2 = 32