A. 6.25
B. 6.5
C. 6.75
D. 7
Explanation:
Required run rate
= [282 – (3.2 * 10)]/40 = 250/40 = 6.25
A. 6.25
B. 6.5
C. 6.75
D. 7
Explanation:
Required run rate
= [282 – (3.2 * 10)]/40 = 250/40 = 6.25
A. 2
B. 4
C. 70
D. 76
Explanation:
Average after 11 innings = 36
Required number of runs
= (36 * 11) – (32 * 10) = 396 – 320 = 76
A. 15 years
B. 17 years
C. 18 years
D. 19 years
Explanation:
Sum of the ages of 14 students
= (16 * 35) – (14 * 21) = 560 – 294 = 266
Required average = (266/14) = 19 years
A. 25
B. 27
C. 30
D. 35
Explanation:
Excluded number = (27 * 5) – (25 * 4) = 135 – 100 = 35.
A. 250
B. 276
C. 280
D. 285
Explanation:
Since the month begins with a Sunday, so there will be five Sundays in the month.
Required average = [(510 * 5) + (240 * 25)]/30 = 8550/30 = 285
A. 28 4/7 years
B. 31 5/7 years
C. 32 1/7 years
D. None of these
Explanation:
Required Average = [(67 * 2) + (35 * 2 ) + (6 * 3)]/(2 + 2 + 3)
= (134 + 70 + 18)/7 = 31 5/7 years.
A. 2
B. 5
C. 8
D. Cannot be determined
Let the numbers x, x + 2, x + 4, x + 6 and x + 8
Then, [x + (x + 2) + (x + 4) + (x + 6) + (x + 8)]5 = 61
or 5x + 20 = 305 => x = 57
So, required difference = (57 + 8) – 57 = 8
A. 9
B. 17
C. 29
D. 295
Explanation:
Let the number be x. Then,
(x + x2)/2 = 5x => x2 – 9x = 0
=> x(x – 9) = 0
=> x = 0 or x = 9
So, the number is 9
A. 33
B. 44
C. 55
D. 66
Explanation:
Average = (11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99)/9
= [(11 + 99) + (22 + 88) + (33 + 77) + (44 + 66) + 55]/9
= [(4 * 110) + 55]/9 = 495/9 = 55
A. 3
B. 9
C. 12
D. 15
Explanation:
Average = 3(1 + 2 + 3 + 4 + 5)/5 = 45/5 = 9