A. 11
B. 10
C. 12
D. 17
Sum of 10 odd no. = 100
Average = 100/10 = 10
The average of first 10 odd numbers is_____________? Read More »
Arithmetic Mcqs, Average Mcqs, Basic Maths Mcqs, Mathematics Mcqs A. 5
B. 5.5
C. 6.5
D. 6
Sum of 10 natural no. = 110/2 = 55
Average = 55/10 = 5.5
The average of first 10 natural numbers is____________? Read More »
Arithmetic Mcqs, Average Mcqs, Basic Maths Mcqs, Mathematics Mcqs A. 12.9
B. 13.8
C. 15.8
D. 17
Explained by: M. Zeeshan Saleem
Hi Friend !!!
Here is your answer !!!
The odd primes :-
3 , 5 , 7 , 11 , 13 , 17 , 19 , 23 , 29 , 31
Average = 3+5+7+11+13+17+19+23+29+31/10
= 158/10
= 15.8
Hope it helps u ?
The average of first ten prime numbers which are odd is____________? Read More »
Arithmetic Mcqs, Average Mcqs, Basic Maths Mcqs, Mathematics McqsSum of 11 numbers = 11×10.9 = 119.9
Sum of 1st 6 numbers = 6×10.5 = 63
So, sum of last 5 numbers = 119.9-63 = 56.9
And sum of last 6 numbers = 6×11.4 = 68.4
Hence sixth number will be = 68.4-56.9= 11.5
A. 18
B. 22
C. 9
D. 11
The average of first 10 even numbers is___________? Read More »
Arithmetic Mcqs, Average Mcqs, Basic Maths Mcqs, Mathematics Mcqs A. 2.5
B. 2.0
C. 1.75
D. 1.5
E. 1.25
One moves at 60km/h, so in an hour, he’ll travel 60km
The other moves at 40km/h, so in an hour, he’ll travel 40km
This is towards each other, so, in an hour, we can say that they’ll get 60+40=100km closer.
This means that they get closer at 100km/h
Given that we have the distance of 150km, and the speed of closure at 100kmh, we can now use the equation
S=D/T
Rearrange to find T (times both sides by T)
S x T = D (now divide both sides by S)
T=D/S
Time = 150km divided by 100km/h
Time = 1.5 hours
Or one hour and 30 minutes
A. 53.33
B. 54.68
C. 55
D. None of these
55 students get average marks of 55%.
so 55*50=2750
similarly 60*55=3300
& 60*45=2700
now total no of marks obtain by all students of three batches= 2750+3300+2700=8750/=
Total no of students= 55+60+45=160.
By dividing total marks on each student , we get average marks obtain by each student
so 8750/160 = 54.68
Solution Added by: MUHAMMAD SHOAIB
A. 14.85%
B. 9.98%
C. 16.20%
D. 14.50%
Solution by Ahmad hassan :
Actually, the question is this.
If a person sells his car in 50000 rupees and got 17% profit. What will be the profit in percentage if he sold this car in 47000 rupees?
Solution
Profit = 17 %
Sp of car = Rs 50000
Cp = sp/1 + .profit percentage
Cp = 50000/1+.17
Cp= 50000/1.17= Rs 42735.04
Now he wants to sell at Rs 47000
New sp = Rs 47000
Profit sp-cp = 47000-42735.04 = Rs 4264.96
Profit % = profitx100/cp
Profit % = 4264.96×100/42735.04 = 9.98 %
New profit % = 9.98
___________________________________________
Solution by Vicky :
total sold price with 17% profit =50,000 (Including 17% profit)
now lets break this 50,000
50,000=X(original cost of car)+0.17x(17% profit) :- x is supposed cars original price
50,000=x+0.17x
x=50,000/1.17 (By taking x common)
x=42,735 (which is Original cost of car)
now again his is selling his damn car at Rs 47,000, that means his profit this time will be
47,000-42,735(original amount of car we just calculated above)=4265 (profit this time)
now calculate the percentage of this above calculated Profit with simple formula
4265/42735*100= 9.98% (Answer) cheers
