QuizMaster

Question: Lock and key theory is based on the compatibility of
[A].

enzyme and substrate

[B].

enzyme and product

[C].

enzyme and enzyme substrate complex

[D].

enzyme substrate complex and product

Answer: Option A

Explanation:

No answer description available for this question.

Question: In the steady state the material balance equation for any component of a system is
[A].

rate of addition + rate of removal – rate of formation = 0

[B].

rate of addition – rate of removal + rate of formation = 0

[C].

rate of addition + rate of removal + rate of formation = 0

[D].

none of the above

Answer: Option B

Explanation:

No answer description available for this question.

Question: Quasi steady state is also known as
[A].

Michaelis Menten approach

[B].

Briggs-Haldane approach

[C].

Pseudo steady state

[D].

all of the above

Answer: Option C

Explanation:

No answer description available for this question.

Question: The slope of Lineweaver Burk plot for Michaelis Menten equation is
[A].

Vmax/Km

[B].

Km/Vmax

[C].

1/Km

[D].

Km.Vmax

Answer: Option B

Explanation:

No answer description available for this question.

Question: The Woolf-Augusteinsson-Hofstee plot of ν versus ν/[S] and the Eadie-Scatchard plot of ν/[S] versus ν do not involve reciprocals of ν therefore are considered to be more reliable when the error in v is
[A].

non-significant

[B].

significant

[C].

nothing to do with the reliability

[D].

non significant in selected cases

Answer: Option B

Explanation:

No answer description available for this question.

Question: An enzyme is assayed at an initial substrate concentration of 2 x 10-5M. In 6 minute, half of the substrate is used. The Km for the substrate is 2 x 10-3M. The value of k in minute is
[A].

0.115

[B].

0.42

[C].

0.093

[D].

6.693

Answer: Option A

Explanation:

No answer description available for this question.

Question: The usual method(s) to solve rate equation of simple enzyme kinetics is/are
[A].

Michaelis Menten approach

[B].

Briggs-Haldane approach

[C].

Numerical solution approach

[D].

all of these

Answer: Option D

Explanation:

No answer description available for this question.

Question: Which of the following statements is true for enzymatically catalyzed reaction?
[A].

The activation energy of the reaction is lowered so that a larger proportion of the substrate qualifies to overcome it

[B].

Additional substrate molecules are energized to overcome the activation energy of the reaction

[C].

The activation energy of the reaction is increased, thus decreasing the likelihood that any substrate molecules will overcome it

[D].

The activation energy of the reaction is lowered so that a fewer substrate molecules can overcome it

Answer: Option A

Explanation:

No answer description available for this question.