Which of the following step is assumed to be the slowest step in the Michaelis Menten equation?

Question: Which of the following step is assumed to be the slowest step in the Michaelis Menten equation?
[A].

The substrate consuming step

[B].

The product releasing step

[C].

Formation of enzyme substrate complex

[D].

None of these

Answer: Option B

Explanation:

No answer description available for this question.

For an enzyme that displays Michaelis-Menten kinetics, the reaction velocity (as a fraction of Vmax) observed at [S] = 2 KM will be

Question: For an enzyme that displays Michaelis-Menten kinetics, the reaction velocity (as a fraction of Vmax) observed at [S] = 2 KM will be
[A].

0.09

[B].

0.33

[C].

0.66

[D].

0.91

Answer: Option C

Explanation:

No answer description available for this question.

Given an enzyme with a Km = 10m M and Vmax = 100 m mol/min. If [S] = 100 m M, which of the following will be true?

Question: Given an enzyme with a Km = 10m M and Vmax = 100 m mol/min. If [S] = 100 m M, which of the following will be true?
[A].

A 10 fold increase in Vmax would increase velocity 10 fold y

[B].

A 10 fold decrease in Km would increase velocity

[C].

Both (a) and (b)

[D].

A 10 fold increase in Vmax would decrease velocity 20 fold

Answer: Option A

Explanation:

No answer description available for this question.

The equation for the rate of product formation for simple enzyme reaction is given by (Where rmax, maximum reaction rate, Cs substrate concentration, Cp product concentration ES, CES enzyme-substrate concentration)

Question: The equation for the rate of product formation for simple enzyme reaction is given by (Where rmax, maximum reaction rate, Cs substrate concentration, Cp product concentration ES, CES enzyme-substrate concentration)
[A].

rp = rmax Cs/(Km+Cs)

[B].

rp= rmax CES/(Km+ CES)

[C].

rp = rmax Cs/(Km+CES)

[D].

rp = rmax Cs/(Km+Cp)

Answer: Option A

Explanation:

No answer description available for this question.