An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent?
A. 3
B. 4
C. 5
D. 6
HCF of 4956, 3894 = 354
(4956 – 3894)/354 = 3
A. 3
B. 4
C. 5
D. 6
HCF of 4956, 3894 = 354
(4956 – 3894)/354 = 3
A. 6.25
B. 6.5
C. 6.75
D. 7
Explanation:
Required run rate
= [282 – (3.2 * 10)]/40 = 250/40 = 6.25
A. 10 seconds
B. 15 seconds
C. 20 seconds
D. 12 seconds
E. None of these
Explanation:
Speed of the boat downstream = 15 + 3 = 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 60 m = 60/5 = 12 seconds.
A. 133.33 kmph
B. 1.33 kmph
C. 4 kmph
D. 8 kmph
He crosses 0.4 km in 3/60th of an hour. Speed = 0.4/(1/20) = 8 kmph
A. 8 : 9
B. 17 : 18
C. 21 : 22
D. Cannot be determined
Originally, let the number of boys and girls in the college be 7x and 8x respectively. Their increased number is (120% of 7x) and (110% of 8x), i . e . ( 120/100 X 7x ) and ( 110/100 X 8x ) i . e . 42x/5 and 44x/5 Required ratio = 42x/5 : 44x/5 = 21 : 22
A. Rs.1000
B. Rs.600
C. Rs.800
D. Rs.400
Explanation:
2*12 : 3*12 : 4*24
1: 3: 4
1/8 * 3200 = 400
A. 70, 50
B. 60, 60
C. 50, 70
D. 40, 80
Let the number of boys be x.
Number of girls is 120 – x.
Total number of chocolates received by boys and girls = 2x + 3(120 – x) = 300
=> 360 – x = 300 => x = 60.
So, the number of boys or girls is 60