A. 2R cm2
B. R2 cm2
C. 1/2 R2 cm2
D. 2 R2 cm2
Explanation:
Area of the largest triangle =(1/2 x 2r x r) Sq.cm =r2 Sq.cm
A. 7 years
B. 11 years
C. 18 years
D. 27 years
9 * 2 = 18 years
A. 120, 40, 60 days
B. 120, 60, 80 days
C. 40, 30, 120 days
D. 30, 40, 60 days
Let a: be the time in which X & Y completes their work = 30 days
b: time in which Y & Z completes their work = 24 days
c: time in which X & Z completes their work = 40 days
X alone can complete the work in (2 * a * c) / (ab + bc – ac) days
= 2 * 30 * 24 * 40 / ((30 * 24) + (24 * 40) – (30 * 40)) = 120 days
Y alone can complete the work in 2 * a * b * c / (- ab + bc + ac) days
= 2 * 30 * 24 * 40 / (-(30 * 24) + (24 * 40) + (30 * 40)) = 40 days
Z alone can complete the work in 2 * a * b * c / (ab – bc + ac) days
= 2 * 30 * 24 * 40 / ((30 * 24) – (24 * 40) + (30 * 40))
= 60 days
A. 5 kmph
B. 6 kmph
C. 7 kmph
D. 8 kmph
Explanation:
Speed downstream = d/t = 85/(2 1/2) = 34 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (34 – 18)/2 = 8 kmph
A. 101
B. 107
C. 111
D. 185
Explanation:
Let the numbers be 37a and 37b.
Then, 37a * 37 b = 4107 => ab = 3
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 * 1, 37 * 3) i.e., (1, 111).
Greater number = 111.
A. 30 days
B. 25 days
C. 24 days
D. 20 days
Part of work done by 1 man in a day = 1/m Part of work done by 1 woman in a day
= 1/w (2/m)+(12/w) = (1/4) (4/m)+(6/w) = (1/5) Solving,
1/m = 1/40 ,1/w = 1/60 (1/m)+(1/w) = 5/120 = 1/24
A. 10/17
B. 10/19
C. 46/105
D. Cannot be determined
Explanation:
There is no definite formula for finding prime numbers among 15 consecutive numbers. Hence the probability cannot be determined.