A. 44 cm
B. 46 cm
C. 48 cm
D. 49 cm
A. Rs. 3500
B. Rs. 4000
C. Rs. 4050
D. Rs. 5000
Explanation:
Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (5050 * 2) = 10100 — (i)
Q + R = (6250 * 2) = 12500 — (ii)
P + R = (5200 * 2) = 10400 — (iii)
Adding (i), (ii) and (iii), we get:
2(P + Q + R) = 33000 = P + Q + R = 16500 — (iv)
Subtracting (ii) from (iv), we get, P = 4000.
P’s monthly income = Rs. 4000
A. Rs.12000
B. Rs.14200
C. Rs.17520
D. Rs.13500
Explanation:
P = (184*106) / [6 2/3 * 6 2/3 *(300*6 2/3)]
P = 13500
A. 6 min. to empty
B. 6 min. to full
C. 9 min. to empty
D. 9 min. to full
Explanation:
Clearly, pipe B is faster than pipe A and so, the tank will be emptied.
Part to be emptied = 2/5
Part emptied by (A + B) in 1 minute = (1/6 – 1/10) = 1/15
1/15 : 2/5 :: 1 : x
x = (2/5 * 1 * 15) = 6 min.
So, the tank will be emptied in 6 min.
A. 8% p.a.
B. 6% p.a.
C. 4% p.a.
D. 5% p.a.
E. None of these
Explanation:
Let the rate of interest be R% p.a.
17400[1 + R/100]2 = 17400 + 1783.50
[1 + R/100]2 = (17400 + 1783.50)/17400
= 1 + 1025/10000 = 1 + 41/400
= 441/400 = [21/20]2
[1 + R/100] = 21/20
R/100 = 1/20
Therefore R = 5
A. Rs.350
B. Rs.375
C. Rs. 380
D. Rs. 400
Explanation:
The principle is P.
P(1 +10/100)2 – P = 420
=> P = Rs.2000
S.I = Rs.(4000/100) = Rs.400
A. (7 , 3) km/hr
B. (6 , 4) km/hr
C. (10 , 4) km/hr
D. None of these
If x: speed of boats man in still water
y: speed of the river
Downstream speed (Ds) = x + y
Upstream speed (Us) = x – y
x = (Ds + Us) / 2
y = (Ds – Us) / 2
In the above problem Ds = 10 ; Us = 4
x = (10 + 4) / 2 = 14/2 = 7 km/hr
y = (10 – 4)/2 = 6/2 = 3 km/hr