A. A
B. B
C. C
D. All Alike
Let B = 100
A = 50
C * (150/100) = 50
3C = 100
C = 33.3 then ‘C’ Cheapest
A. 68 4/7 %
B. 78 %
C. 80 %
D. 80 4/7 %
Explanation:
Total candidates = (100 + 75) = 175
Total passed = (75/100 × 100) + (60/100 × 75)
= (75 + 45) = 120
Therefore Pass % = (120/175 × 100)%
= 480/7 % = 68 4/7 %
A. 0.03
B. 0.9
C. 0.18
D. 0.108
Explanation:
Given numbers are 1.08, 0.36 and 0.90.
H.C.F of 108, 36 and 90 is 18.
H.C.F of a given numbers = 0.18
A. 1580
B. 1680
C. 1780
D. 1880
Explanation:
59000 / 364 * 11 = ?
=> ? = 162 * 11 = 1782 = 1780
A. 180
B. 170
C. 190
D. 175
Explanation:
Let the five numbers be P, Q, R, S and T.
=> P + Q + R + S + T = 655.
(P + Q)/2 = 85 and R = 125
P + Q = 170 and R = 125
P + Q + R = 295
S + T = 655 – (P + Q + R) = 360
Average of the last two numbers = (S + T)/2 = 180
A. 500
B. 1200
C. 1000
D. 1625
Percentage of failure = (100 – 65) % = 35 %
Let the total number of examinees be x.
Then 35 % of x = 420
=> 35/100 × x = 420
=> x =(420 × 100/35) = 1200
A. Rs.45
B. Rs.78
C. Rs.44
D. Rs.40
π (152 – 132) = 176
176 * 1/4 = Rs.44