A. 12 days
B. 15 days
C. 16 days
D. 18 days
A. 26
B. 28
C. 30
D. 32
Explanation:
Let A = Set of students who fail in English
B = Set of students who fair in mathematics
Then , n(A) = 50, n(B) = 30 and n(A∩ B) = 12.
n(AUB) = n(A) + n(B)- n(A∩B) = (50 + 30 -12) = 68
Number of students who fail in one or both the students = 68
Number of those who pass in both = (100 – 68) = 32
A. Rs.357
B. Rs.340
C. Rs.342
D. Rs.338
Explanation:
400*(90/100)*(95/100) = 342
A. 30 π cc
B. 45 π cc
C. 150 π cc
D. 180 π cc
r = 3 h = 5
π * 3 * 3 * 5 = 45 π cc
A. 10 %
B. 15 %
C. 20 %
D. 25 %
Explanation:
Let the 3rd number be 100.
Then 1st number = 70,
2nd number = 63
2nd number is less than 1st by = (7/70 ×100) % = 10 %
A. 1
B. 117
C. equal to their H.C.F
D. Cannot be calculated
Explanation:
H.C.F of co-prime numbers is 1.
So, L.C.M = 117/1 = 117.
A. 125
B. 134
C. 170
D. 98
Sum of the 35 numbers = 35 * 25 = 875
If each number is multiplied by 5, the sum also gets multiplied by 5 and the average also gets multiplied by 5.
Thus, the new average = 25 * 5 = 125