A. 2:5
B. 3:4
C. 3:5
D. 1:2
A. 17.5cm
B. 21cm
C. 28cm
D. None of these
A. 120, 40, 60 days
B. 120, 60, 80 days
C. 40, 30, 120 days
D. 30, 40, 60 days
Let a: be the time in which X & Y completes their work = 30 days
b: time in which Y & Z completes their work = 24 days
c: time in which X & Z completes their work = 40 days
X alone can complete the work in (2 * a * c) / (ab + bc – ac) days
= 2 * 30 * 24 * 40 / ((30 * 24) + (24 * 40) – (30 * 40)) = 120 days
Y alone can complete the work in 2 * a * b * c / (- ab + bc + ac) days
= 2 * 30 * 24 * 40 / (-(30 * 24) + (24 * 40) + (30 * 40)) = 40 days
Z alone can complete the work in 2 * a * b * c / (ab – bc + ac) days
= 2 * 30 * 24 * 40 / ((30 * 24) – (24 * 40) + (30 * 40))
= 60 days
A. 4 days
B. 6 days
C. 8 days
D. 12 days
(A + B + C)’s 1 day’s work = 1/6; (A + B)’s 1 day’s work = 1/8 (B + C)’s 1 day’s work = 1/12 (A + C)’s 1 day’s work = ( 2 X 1/6 ) – ( 1/8 + 1/12 ) = ( 1/3 – 5/24 ) = 3/24 = 1/8 So, A and C together will do the woirk in 8 days.
A. Rs.250
B. Rs.225
C. Rs.275
D. Rs.200
Explanation:
CP1 = 100 SP1 = 90
CP2 = 80 SP2 = 80 * (140/100) = 112
22 —– 100
55 —– ? => Rs.250
A. 6 min. to empty
B. 6 min. to full
C. 9 min. to empty
D. 9 min. to full
Explanation:
Clearly, pipe B is faster than pipe A and so, the tank will be emptied.
Part to be emptied = 2/5
Part emptied by (A + B) in 1 minute = (1/6 – 1/10) = 1/15
1/15 : 2/5 :: 1 : x
x = (2/5 * 1 * 15) = 6 min.
So, the tank will be emptied in 6 min.
A. 16%
B. 16 1/3 %
C. 20%
D. 16 3/5 %
X=100 y=125
125——–25
100——–? => 20%