Reynold’s analogy states that (where, St = Stanton number f = friction factor) ? / Chemical Engineering / Q&A, MCQs / Q&A / By admin Reynold’s analogy states that (where, St = Stanton number f = friction factor) ? A. St = f/2 (Correct) B. St = f/4 C. St = 4f D. St = f1/2
