A total of 324 coins of 20 paise and 25 paise make a sum of Rs. 71. The number of 25-paise coins is

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Question: A total of 324 coins of 20 paise and 25 paise make a sum of Rs. 71. The number of 25-paise coins is
[A].

120

[B].

124

[C].

144

[D].

200

Answer: Option B

Explanation:

Let the number of 20-paise coins be x. Then, number of 25-paise coins = (324 – x).

Therefore 0.20 x x + 0.25 (324 – x) = 71 20x + 25 (324 – x) = 7100

5x= 1000 x = 200. Hence, number of 25-paise coins = (324 – x) – 124.

In order to create one solid model from two or more separate solid shapes the drafter will need to position them and then ________.

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Question: In order to create one solid model from two or more separate solid shapes the drafter will need to position them and then ________.
[A].

use Union to join them

[B].

use the Join command

[C].

use the Add Parts tool

[D].

none of the above

Answer: Option A

Explanation:

No answer description available for this question.

In three coloured boxes – Red, Green and Blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ?

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Question: In three coloured boxes – Red, Green and Blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ?
[A].

18

[B].

36

[C].

45

[D].

None of these

Answer: Option D

Explanation:

Let R, G and B represent the number of balls in red, green and blue boxes respectively.

Then, .

R + G + B = 108 …(i),

G + R = 2B …(ii)

B = 2R …(iii)

From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.

Putting G = 3R and B = 2R in (i), we get:

R + 3R + 2R = 108 6R = 108 R = 18.

Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.