Question: In a totally irreversible isothermal expansion process for an ideal gas, ΔE = 0, ΔH = 0. Then ΔQ and ΔS will be
[A].ΔQ = 0, ΔS=0
ΔQ = 0 , ΔS = +ve
ΔQ = 0, ΔS = -ve
ΔQ = +ve , ΔS= +ve
[A].
[B].
[C].
[D].
Answer: Option B
Explanation:
No answer description available for this question.