In a totally irreversible isothermal expansion process for an ideal gas, ΔE = 0, ΔH = 0. Then ΔQ and ΔS will be

Question: In a totally irreversible isothermal expansion process for an ideal gas, ΔE = 0, ΔH = 0. Then ΔQ and ΔS will be
[A].

ΔQ = 0, ΔS=0

[B].

ΔQ = 0 , ΔS = +ve

[C].

ΔQ = 0, ΔS = -ve

[D].

ΔQ = +ve , ΔS= +ve

Answer: Option B

Explanation:

No answer description available for this question.