Find the Missing Number in the series 1, 6, 13, 22, 33 ?
Find the Missing Number in the series 1, 6, 13, 22, 33 ?
A. 36
B. 40
C. 46
D. 52
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Find the average of the first 20 natural numbers?
Find the average of the first 20 natural numbers?A. 10
B. 11.5
C. 12
D. 10.5
Explanation:
Average of the first ‘n’ natural numbers = (n + 1)/2
We get (20 + 1)/2 = 10.5A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man’s rate is________?
A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man’s rate is________?A. 1 kmph
B. 5 kmph
C. 8 kmph
D. 3 kmph
Explanation:
DS = 6
US = 4
S = ?
S = (6 – 4)/2 = 1 kmphRs. 395 are divided among A, B and C ins such a manner that B gets 25 % more than A and 20 % more than C. The share of A is:
Rs. 395 are divided among A, B and C ins such a manner that B gets 25 % more than A and 20 % more than C. The of A is:A. Rs. 198
B. Rs. 120
C. Rs. 180
D. Rs. 195
Explanation:
Suppose A gets Rs. x.
Then B gets 125 % of x = 125/100 × x = Rs. 5x/4
If B gets Rs. 120.
Then c gets Rs. 100
If B gets Rs 5x/4, then c gets = Rs (100/120 ×5x/4)
= Rs 25x/24 x + 5x/4 + 25x/24 = 395
=> (24x + 30x + 25x) = (395 × 24)
=>79x = (395 × 24)
= > x = ((395 ×24)/79) = 120
Hence, A gets Rs. 120A man travels from A to B at a speed of 30 kmph and returns with a speed of 60 kmph. What is the average speed of the man?
A man travels from A to B at a speed of 30 kmph and returns with a speed of 60 kmph. What is the average speed of the man?A. 47.5
B. 50
C. 45
D. 4040% of Raees marks is equal to 20% of Rahim’s marks which percent is equal to 30% of Rehman’s marks. If Rehman’s marks is 80, then find the average marks of Raees and Rahim?
40% of Raees marks is equal to 20% of Rahim’s marks which percent is equal to 30% of Rehman’s marks. If Rehman’s marks is 80, then find the average marks of Raees and Rahim?A. 60
B. 70
C. 80
D. 90
E. None of these
Explanation:
Given, 40% of Ram’s marks = 20% of Rahim’s marks = 30% of Robert’s marks.
Given, marks of Robert = 80
30% of 80 = 30/100 * 8 = 24
Given, 40% of Ram’s marks = 24.
=> Ram’s marks = (24 * 100)/40 = 60
Also, 20% of Rahim’s marks = 24
=> Rahim’s marks = (24 * 100)/20 = 120
Average marks of Ram and Rahim = (60 + 120)/2 = 90.The arithmetic mean of the scores of a group of students in a test was 52. The brightest 20% of them secured a mean score of 80 and the dullest 25% a mean score of 31. The mean score of remaining 55% is___________?
The arithmetic mean of the scores of a group of students in a test was 52. The brightest 20% of them secured a mean score of 80 and the dullest 25% a mean score of 31. The mean score of remaining 55% is___________?A. 45
B. 50
C. 51.4 approx.
D. 54.6 approx.
Explanation:
Let the required means score be x. Then,
20 * 80 + 25 * 31 + 55 * x = 52 * 100
= 1600 + 775 + 55x = 5200
= 55x = 2825
= x = 565/11 = 51.4.