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FeO (s) + CO (g) = Fe (s) + CO2 (g), k = 0. 435 at 1173E; At equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173 K?

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Question: FeO (s) + CO (g) = Fe (s) + CO2 (g), k = 0. 435 at 1173E; At equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173 K?
[A].

1.0

[B].

1.3

[C].

2.3

[D].

3.3

Answer: Option D

Explanation:

No answer description available for this question.