A. 300 km
B. 290 km
C. 250 km
D. 240 km
Total distance = (120*2) + (100*(1/2)) = 290 km
A. 300 km
B. 290 km
C. 250 km
D. 240 km
Total distance = (120*2) + (100*(1/2)) = 290 km
A. 8 kmph
B. 11 kmph
C. 12 kmph
D. 14 kmph
A. 30 km
B. 40 km
C. 70 km
D. 80 km
A. 5 km
B. 5.5 km
C. 6 km
D. 6.5 km
Average speed = ( 2 X 3 X 2/3 + 2 ) km/ hr = 12/5 km/ hr. Distance travelled = ( 12/5 X 5 )km = 12 km. So Distance between house and school = ( 12/2 )km = 6 km.
A. 6 hrs 21 min
B. 6 hrs 24 min
C. 6 hrs 27 min
D. 6 hrs 30 min
Time taken to cover 600 km = ( 600/100 ) hrs = 6 hrs. Number of stoppages = ( 600/75 – 1 ) = 7 Total time of stoppage = (3 x 7) min = 21 min. Hence, total time taken = 6 hrs 21 min.
A. 7.42 a.m.
B. 7.48 a.m.
C. 8.10 a.m.
D. 8.30 a.m.
A. 220 km
B. 224 km
C. 230 km
D. 234 km
A. 45 metres
B. 55 metres
C. 450 metres
D. Cannot be determined
A. 10 min
B. 11 min 20 sec
C. 13 min
D. 13 min 20 sec
Speed = (10 X 60/12 ) km/hr = 50 km/hr. New speed = (50 – 5) km / hr = 45 km /hr. So Time taken = ( 10/45 ) hr = ( 2/9X 60 )min 131/3 min = 13 min 20 sec.
A. 2.5
B. 2.0
C. 1.75
D. 1.5
E. 1.25
One moves at 60km/h, so in an hour, he’ll travel 60km
The other moves at 40km/h, so in an hour, he’ll travel 40km
This is towards each other, so, in an hour, we can say that they’ll get 60+40=100km closer.
This means that they get closer at 100km/h
Given that we have the distance of 150km, and the speed of closure at 100kmh, we can now use the equation
S=D/T
Rearrange to find T (times both sides by T)
S x T = D (now divide both sides by S)
T=D/S
Time = 150km divided by 100km/h
Time = 1.5 hours
Or one hour and 30 minutes