Find the C.I. on a sum of Rs.1600 for 9 months at 20% per annum, interest being compounded quarterly?
A. Rs.17684
B. Rs.1684
C. Rs.2522
D. Rs.3408
Explanation:
A = 1600(21/20)3 = 2522
A. Rs.17684
B. Rs.1684
C. Rs.2522
D. Rs.3408
Explanation:
A = 1600(21/20)3 = 2522
A. Rs.6620
B. Rs.6500
C. Rs.6800
D. Rs.6400
Explanation:
A = 20000(11/10)3
= 26620
= 20000
———-
6620
A. 4 years
B. 6 years
C. 2 years
D. 3 years
Explanation:
9261 = 8000(21/20)N
(21/20)3 = (21/20)N => N = 3
A. Rs.420.20
B. Rs.319.06
C. Rs.306.04
D. Rs.294.75
Explanation:
A = 5000(51/50)3
= 5306.04
5000
———–
306.04
Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years. Read More »
Compound Interest, Mathematics Mcqs A. Rs.8082
B. Rs.7800
C. Rs.8100
D. Rs.8112
Explanation:
A = 7500(26/25)2 = 8112
A. Rs.1261
B. Rs.1440
C. Rs.1185
D. Rs.1346
Explanation:
A = 8000(21/20)3
= 9261
= 8000
———
1261
A. 50km
B. 60km
C. 70km
D. 80 km
Explanation:
Let the distance between the two parts be x km.
Then speed downstream = x/4 km/hr.
Speed Upstream = x/5 km/hr
Speed of the stream = ½ (x/4 –x/5)
Therefore, ½(x/4 –x/5) = 2. => x/4 –x/5 = 4 => x = 80.
Hence, the distance between the two ports is 80km.
A. 5 hours 50 min
B. 6 hours
C. 6 hours 50 min
D. 12 hours 10 min
Explanation:
Let the speed of motor boat be 36x km/hr and that of current of water be 5x km/hr
Speed downstream = (36x +5x)km/hr = 41x km/hr
Speed upstream = (36 -5x)km/hr = 31x km/hr
Distance covered downstream = (41x × 31/6)km
Distance upstream = [1271x/6 × 1/31x]hrs
= 41/6 hrs = 6hrs 50 min
A. 5km/hr
B. 8 km/hr
C. 10 km/hr
D. 15 km/hr
A. 8km/hr
B. 12km/hr
C. 14 km/hr
D. 15 km/hr
E. None of these
Explanation:
Speed downstream = (30 x 2/5)km/hr = 12km/hr
Speed upstream = (30 x 4/15) km/hr = 8 km/hr
Speed of boat in still water = ½ (12 + 8)km/hr = 10 km/hr