Mathematics Mcqs

A. 1
B. 5
C. 10
D. 25
10 workers make 10 tables in 10 days. 1 worker makes 1 table in 10 days. Similarly, 5 workers can make 5 tables in 10 days.

A. 2 men
B. 12 men
C. 9 men
D. 18 men
For the work to be completed in 9 days,
6 men are required. Time and men are inversely proportional. For the work to be completed in 3 days,
6*9/3 = 18 men are required

A. Rs.1104
B. Rs.1000
C. Rs.934
D. Rs.1210
Assume that cost of keeg a cow for 1 day = c ,
cost of keeg a goat for 1 day = g
Cost of keeg 20 cows and 40 goats for 10 days = 460
Cost of keeg 20 cows and 40 goats for 1 day = 460/10 = 46
=> 20c + 40g = 46
=> 10c + 20g = 23 —(1)
Given that 5g = c
Hence equation (1) can be written as 10c + 4c = 23 => 14c =23
=> c=23/14
cost of keeg 50 cows and 30 goats for 1 day
= 50c + 30g
= 50c + 6c (substituted 5g = c)
= 56 c = 56×23/14
= 92
Cost of keeg 50 cows and 30 goats for 12 days = 12×92 = 1104

A. 7
B. 8
C. 9
D. 6
Let P takes x days to complete the work
Then Q takes x/2 days and R takes x/3 days to finish the work
Amount of work P does in 1 day = 1/x
Amount of work Q does in 1 day = 2/x
Amount of work R does in 1 day = 3/x
Amount of work P,Q and R do in 1 day = 1/x + 2/x + 3/x = 1/x (1 + 2 + 3) = 6/x
6/x = 2
=> x = 12
=> Q takes 12/2 days = 6 days to complete the work

A. 50
B. 30
C. 40
D. 13
Work done by 4 men and 6 women in 1 day = 1/8
Work done by 3 men and 7 women in 1 day = 1/10
Let 1 man does m work in 1 day and 1 woman does w work in 1 day. The above equations can be written as
4m + 6w = 1/8 —(1)
3m + 7w = 1/10 —(2)
Solving equation (1) and (2) , we get m=11/400 and w=1/400
Amount of work 10 women can do in a day = 10 × (1/400) = 1/40
Ie, 10 women can complete the work in 40 days

A. 10 days
B. 14 days
C. 15 days
D. 9 days

A. 10 min
B. 20 min
C. 30 min
D. 40 min

A. 15 days
B. 14 days
C. 16 days
D. 30 days
Raio of times taken by A and B = 1 : 3
If the difference of time is 2 days, B takes 3 days. If the difference of time is 10 days.
B takes [3/2×10]=15 days

A. 6 days
B. 8 days
C. 10 days
D. 12 days
2 children = 1 man
(8 children + 12 men ) = 16 men
Now, less men, more days
12 : 16 : 9 : x
x = 16×9/12=12 days

A. 48 days
B. 24 days
C. 40 days
D. 36 days
No. of days is
directly proportional to the length of the wall and
inversely proportional to the number of men No. of days = (1200/500)*(15/30)*30 = 36 days