In an examination, 65 % of the total examinees passed if the number of failures is 420, the total number of examinees is:_________?

In an examination, 65 % of the total examinees passed if the number of failures is 420, the total number of examinees is:_________?

A. 500
B. 1200
C. 1000
D. 1625
Percentage of failure = (100 – 65) % = 35 %
Let the total number of examinees be x.
Then 35 % of x = 420
=> 35/100 × x = 420
=> x =(420 × 100/35) = 1200

Rs. 395 are divided among A, B and C ins such a manner that B gets 25 % more than A and 20 % more than C. The share of A is:

Rs. 395 are divided among A, B and C ins such a manner that B gets 25 % more than A and 20 % more than C. The of A is:

A. Rs. 198
B. Rs. 120
C. Rs. 180
D. Rs. 195
Explanation:
Suppose A gets Rs. x.
Then B gets 125 % of x = 125/100 × x = Rs. 5x/4
If B gets Rs. 120.
Then c gets Rs. 100
If B gets Rs 5x/4, then c gets = Rs (100/120 ×5x/4)
= Rs 25x/24 x + 5x/4 + 25x/24 = 395
=> (24x + 30x + 25x) = (395 × 24)
=>79x = (395 × 24)
= > x = ((395 ×24)/79) = 120
Hence, A gets Rs. 120

605 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20 % of the total number of children. How many sweets did each child receive?

605 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20 % of the total number of children. How many sweets did each child receive?

A. 11
B. 24
C. 45
D. cannot be determined
Let the total number of children be x.
Then x × 20/100 × x = 605
=> x2 = 3025
=> x = √3025 = 55
Number of sweets received by each child
= (20/100 ×55) = 11

Two numbers are less than q third number by 30 % and 37 % respectively. How much percent is the second number less than the first?

Two numbers are less than q third number by 30 % and 37 % respectively. How much percent is the second number less than the first?

A. 10 %
B. 15 %
C. 20 %
D. 25 %
Explanation:
Let the 3rd number be 100.
Then 1st number = 70,
2nd number = 63
2nd number is less than 1st by = (7/70 ×100) % = 10 %

The length of a rectangle is increased by 60 %. By what percent would the width have to be decreased to maintain the same area?

The length of a rectangle is increased by 60 %. By what percent would the width have to be decreased to maintain the same area?

A. 37 ½ %
B. 60 %
C. 75 %
D. none of these
Explanation:
Let length = 100 m.
Breath = 100 m.
New length = 160 m.
New breath = x meters
Then, = 160 × x = 100 × 100
(or) X = (100 ×100)/160 × 125/2
Decrease in breadth = (100- 125/2) % = 37 ½ %

The price of an article has been reduced by 25 %. In order to restore the original price, the new price must be increased by:________?

The price of an article has been reduced by 25 %. In order to restore the original price, the new price must be increased by:________?

A. 33 1/3 %
B. 11 1/9 %
C. 9 1/11 %
D. 66 2/3 %
Explanation:
Let original price = Rs. 100.
Reduced Price = Rs. 75.
Increase on Rs. 75 = Rs. 25
Increase on 100 = (25/75 x 100) % = 33 1/3 %

A man’s basic pay for a 40 hour week is Rs. 20 overtime is paid for at 25 % above the basic rate, in a certain week he worked overtime and his total wage was Rs. 25. He therefore worked for a total of:________?

A man’s basic pay for a 40 hour week is Rs. 20 overtime is paid for at 25 % above the basic rate, in a certain week he worked overtime and his total wage was Rs. 25. He therefore worked for a total of:________?

A. 45 hours
B. 47 hours
C. 48 hours
D. 50 hours
Explanation:
Basic rate per hour = Re. (20/40) = Re. 1/2.
Overtime per hour = 125 % of Re. 1/2 = Re.5/8.
He worked x hours overtime.
Then 20 + 5/8 x = 25 (or) = 5/8 x = 5
X = 40/5 = 8 hours
=> he worked in all for (40 + 8) = 48 hours.