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Mathematics Mcqs

One Gross is equal to___________?

One Gross is equal to___________?A. 5 Dozen
B. 10 Dozen
C. 12 Dozen
D. None of them

A gross refers to a group of 144 items (a dozen dozen or a square dozen, 122). A great gross refers to a group of 1728 items (a dozen gross or a cubic dozen, 123). A small gross or a great hundred refers to a group of 120 items (ten dozen, 10×12).

One Gross is equal to___________? Read More »

Everyday Science Mcqs, Mathematics Mcqs

A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the joɡɡer?

A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the joɡɡer?

A. 3.6 sec
B. 18 sec
C. 36 sec
D. 72 sec

Explanation
With 5 best steps
1.Data:
Speed 1=V₁= 9km/h
Distance 1=S₁= 240 m
Distance 2 =S₁= 120 m
Speed 2=V₂= 45km/h
Relative speed(V) = V₂_V₁
Relative speed (V)= 45km/h_9 km/h
Relative speed (V)=36km/h
Relative speed(V)= 36×1000m/3600Sec
Relative speed (V)= 36000m/3600Sec
Relative speed(V)= 10 m/sec
Covered distance(S)= 240m+120m
Covered distance (S)= 360m.
2. Required:
Time taken= T=??
3. Formula:
S= V×T
For T
T = S/V
4. Solution:
Putting values in formula.
T= 360 m/10 m/Sec
T= 36Sec
5. Result:
Time taken= T= 36 Sec

A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the joɡɡer? Read More »

Mathematics Mcqs, Time & Distance Mcqs

Three flags each of different colours are available for a military exercise, Using these flags different codes can be generated by waving I. Single flag of different colours II. Any two flags in a different sequence of colours. III. three flags in a different sequence of colours. The maximum number of codes that can be generated is.

Three flags each of different colours are available for a military exercise, Using these flags different codes can be generated by waving
I. Single flag of different colours
II. Any two flags in a different sequence of colours.
III. three flags in a different sequence of colours.
The maximum number of codes that can be generated is.

A. 6
B. 9
C. 15
D. 18
Explanation:
This type of question becomes very easy when we assume three colour are red(R) blue(B) and Green(G).
We can choose any colour.
Now according to the statement 1 i.e.., codes can be generated by waving single flag of different colours, then number of ways are three i.e.., R.B.G from statement III three flags in different sequence of colours, then number of ways are six i.e.., RBG, BGR, GBR, RGB, BRG, GRB.
Hence total number of ways by changing flag = 3+ 6 +6 = 15

Three flags each of different colours are available for a military exercise, Using these flags different codes can be generated by waving I. Single flag of different colours II. Any two flags in a different sequence of colours. III. three flags in a different sequence of colours. The maximum number of codes that can be generated is. Read More »

Mathematics Mcqs, Permutations and Combinations

Two trains are moving in opposite directions 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is_________?

Two trains are moving in opposite directions 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is_________?

A. 36
B. 45
C. 48
D. 49

Explained with 5 Steps.
1.Data:
Speed 1 = 60 km/hr
Speed 2= 90 km/hr
Relative speed= (60+90)km/hr
Relative speed= 150 km/hr
Relative speed= 150×1000m/3600 Sec
Relative speed= 150,000m/3600 Sec
Relative speed= 1500m/36Sec
Relative speed= 42m/Sec
Distance 1= 1.10km
Distance 2= 0.9km
Total distance= (1.10+0.9) km
D(t)= 2 km => 2×1000m
D(t) = 2000m
2 Required:
Time=T=???
3. Formula:
S = V×T
For T
T= S/V
4. Solution:
Putting value in formulas.
T= 2000m/ 42 m/sec
T= 48Sec
5. Result:
Time =T= 48 Sec

Two trains are moving in opposite directions 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is_________? Read More »

Mathematics Mcqs, Time & Distance Mcqs

A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of

A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of

A. 120
B. 260
C. 240
D. 220

Explanation with best method.
5 Steps
1.Data:
Train station platform= 36Sec
Standing platform = 20Sec
Speed of train = 54km/hr
2.Required:
Length of platform= x=???
3.Formula:
X+length of train/Train station platform
4.Solution: first for terms
Speed = 54 ×1000m/3600sec = 15 m/Sec.
Length of the train = (15 m/Sec × 20Sec = 300 m.
Let the length of the platform be x metres.
Now, x + 300m /36Sec= 15 m/Sec
x+300m= 15m/Sec×36Sec
x + 300m = 540m
x= 540m-300m
x = 240 m.
5.Result:
Length of platform=x=240m

A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of Read More »

Mathematics Mcqs, Time & Distance Mcqs

A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?

A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?

A. 80 Sec
B. 89 Sec
C. 90 Sec
D. 95 Sec

Explanation:
Best 5 steps methods.
1.Data:
Distance= d1= 240m
Time =t= 24 Sec
Distance =d2=650
2.Required:
Time =T=??
3. Formula: D=S×T
d1+d2= S× T
Now for T=??
T= d1+d2/S
4.Solution: first for speed
S=d1/t=240m/24Sec = 10 m/Sec
Now for time
T =d1+d2/S
Putting values in T formula.
T= (240 m+ 650 m) /10 m/Sec
T= 890 m/10 m/Sec
T = 89 Sec
5.Result:
T= 89 Seconds

A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long? Read More »

Mathematics Mcqs, Time & Distance Mcqs

Twelve children take sixteen days to complete a work which can be completed by 8 adults in 12 days. After working for 3 days, sixteen adults left and six adults and four children joined them. How many days will they take to complete the remaining work ?

Twelve children take sixteen days to complete a work which can be completed by 8 adults in 12 days. After working for 3 days, sixteen adults left and six adults and four children joined them. How many days will they take to complete the remaining work ?

A. 3 days
B. 4 days
C. 6 days
D. 8 days

Solution:
12×16×C=12×8×A
Or, A:C=2:1 [Efficiency ratio]
Let, Required time be T days
Applying MDH Method:
12×8×2=16×2×3+(6×2+4×1)×T
Or, 192=96+14T
Or, T=6
Answer:6 days

Twelve children take sixteen days to complete a work which can be completed by 8 adults in 12 days. After working for 3 days, sixteen adults left and six adults and four children joined them. How many days will they take to complete the remaining work ? Read More »

Mathematics Mcqs, Time and Work Mcqs