Find the Missing Number in the series 1, 6, 13, 22, 33 ?
A. 36
B. 40
C. 46
D. 52
Find the Missing Number in the series 1, 6, 13, 22, 33 ? Read More »
Arithmetic Mcqs, Mathematics McqsA. 36
B. 40
C. 46
D. 52
Find the Missing Number in the series 1, 6, 13, 22, 33 ? Read More »
Arithmetic Mcqs, Mathematics McqsA gross refers to a group of 144 items (a dozen dozen or a square dozen, 122). A great gross refers to a group of 1728 items (a dozen gross or a cubic dozen, 123). A small gross or a great hundred refers to a group of 120 items (ten dozen, 10×12).
One Gross is equal to___________? Read More »
Everyday Science Mcqs, Mathematics Mcqs A. 3.6 sec
B. 18 sec
C. 36 sec
D. 72 sec
Explanation
With 5 best steps
1.Data:
Speed 1=V₁= 9km/h
Distance 1=S₁= 240 m
Distance 2 =S₁= 120 m
Speed 2=V₂= 45km/h
Relative speed(V) = V₂_V₁
Relative speed (V)= 45km/h_9 km/h
Relative speed (V)=36km/h
Relative speed(V)= 36×1000m/3600Sec
Relative speed (V)= 36000m/3600Sec
Relative speed(V)= 10 m/sec
Covered distance(S)= 240m+120m
Covered distance (S)= 360m.
2. Required:
Time taken= T=??
3. Formula:
S= V×T
For T
T = S/V
4. Solution:
Putting values in formula.
T= 360 m/10 m/Sec
T= 36Sec
5. Result:
Time taken= T= 36 Sec
A. 6
B. 9
C. 15
D. 18
Explanation:
This type of question becomes very easy when we assume three colour are red(R) blue(B) and Green(G).
We can choose any colour.
Now according to the statement 1 i.e.., codes can be generated by waving single flag of different colours, then number of ways are three i.e.., R.B.G from statement III three flags in different sequence of colours, then number of ways are six i.e.., RBG, BGR, GBR, RGB, BRG, GRB.
Hence total number of ways by changing flag = 3+ 6 +6 = 15
A. 36
B. 45
C. 48
D. 49
Explained with 5 Steps.
1.Data:
Speed 1 = 60 km/hr
Speed 2= 90 km/hr
Relative speed= (60+90)km/hr
Relative speed= 150 km/hr
Relative speed= 150×1000m/3600 Sec
Relative speed= 150,000m/3600 Sec
Relative speed= 1500m/36Sec
Relative speed= 42m/Sec
Distance 1= 1.10km
Distance 2= 0.9km
Total distance= (1.10+0.9) km
D(t)= 2 km => 2×1000m
D(t) = 2000m
2 Required:
Time=T=???
3. Formula:
S = V×T
For T
T= S/V
4. Solution:
Putting value in formulas.
T= 2000m/ 42 m/sec
T= 48Sec
5. Result:
Time =T= 48 Sec
A. 120
B. 260
C. 240
D. 220
Explanation with best method.
5 Steps
1.Data:
Train station platform= 36Sec
Standing platform = 20Sec
Speed of train = 54km/hr
2.Required:
Length of platform= x=???
3.Formula:
X+length of train/Train station platform
4.Solution: first for terms
Speed = 54 ×1000m/3600sec = 15 m/Sec.
Length of the train = (15 m/Sec × 20Sec = 300 m.
Let the length of the platform be x metres.
Now, x + 300m /36Sec= 15 m/Sec
x+300m= 15m/Sec×36Sec
x + 300m = 540m
x= 540m-300m
x = 240 m.
5.Result:
Length of platform=x=240m
A. 80 Sec
B. 89 Sec
C. 90 Sec
D. 95 Sec
Explanation:
Best 5 steps methods.
1.Data:
Distance= d1= 240m
Time =t= 24 Sec
Distance =d2=650
2.Required:
Time =T=??
3. Formula: D=S×T
d1+d2= S× T
Now for T=??
T= d1+d2/S
4.Solution: first for speed
S=d1/t=240m/24Sec = 10 m/Sec
Now for time
T =d1+d2/S
Putting values in T formula.
T= (240 m+ 650 m) /10 m/Sec
T= 890 m/10 m/Sec
T = 89 Sec
5.Result:
T= 89 Seconds
Origin lies on the intersection of the x-axis and y-axis, i.e, (0,0).
Co-ordinates of Origin are:___________? Read More »
Mathematics Mcqs A. 3 days
B. 4 days
C. 6 days
D. 8 days
Solution:
12×16×C=12×8×A
Or, A:C=2:1 [Efficiency ratio]
Let, Required time be T days
Applying MDH Method:
12×8×2=16×2×3+(6×2+4×1)×T
Or, 192=96+14T
Or, T=6
Answer:6 days
zero is a__________ number? Read More »
Mathematics Mcqs