A. 12 days
B. 14 days
C. 16 days
D. 18 days
A. 1.8 days
B. 1.5 days
C. 1.2 days
D. 1 day
Time is
directly proportional to number of sofas
inversely proportional to number of people No. of days
= (6/8)*(8/10)*2
= 1.2 days
If 6 men can make 10 sofas in 2 days, then 8 men can make 8 sofas in__________? Read More »
Basic Maths Mcqs, Mathematics Mcqs, Time and Work Mcqs A. 1
B. 5
C. 10
D. 25
10 workers make 10 tables in 10 days. 1 worker makes 1 table in 10 days. Similarly, 5 workers can make 5 tables in 10 days.
A. 2 men
B. 12 men
C. 9 men
D. 18 men
For the work to be completed in 9 days,
6 men are required. Time and men are inversely proportional. For the work to be completed in 3 days,
6*9/3 = 18 men are required
If 6 men take 9 days to complete a work, how many men can complete the work in 3 days? Read More »
Basic Maths Mcqs, Mathematics Mcqs, Time and Work Mcqs A. Rs.1104
B. Rs.1000
C. Rs.934
D. Rs.1210
Assume that cost of keeg a cow for 1 day = c ,
cost of keeg a goat for 1 day = g
Cost of keeg 20 cows and 40 goats for 10 days = 460
Cost of keeg 20 cows and 40 goats for 1 day = 460/10 = 46
=> 20c + 40g = 46
=> 10c + 20g = 23 —(1)
Given that 5g = c
Hence equation (1) can be written as 10c + 4c = 23 => 14c =23
=> c=23/14
cost of keeg 50 cows and 30 goats for 1 day
= 50c + 30g
= 50c + 6c (substituted 5g = c)
= 56 c = 56×23/14
= 92
Cost of keeg 50 cows and 30 goats for 12 days = 12×92 = 1104
A. 7
B. 8
C. 9
D. 6
Let P takes x days to complete the work
Then Q takes x/2 days and R takes x/3 days to finish the work
Amount of work P does in 1 day = 1/x
Amount of work Q does in 1 day = 2/x
Amount of work R does in 1 day = 3/x
Amount of work P,Q and R do in 1 day = 1/x + 2/x + 3/x = 1/x (1 + 2 + 3) = 6/x
6/x = 2
=> x = 12
=> Q takes 12/2 days = 6 days to complete the work
A. 50
B. 30
C. 40
D. 13
Work done by 4 men and 6 women in 1 day = 1/8
Work done by 3 men and 7 women in 1 day = 1/10
Let 1 man does m work in 1 day and 1 woman does w work in 1 day. The above equations can be written as
4m + 6w = 1/8 —(1)
3m + 7w = 1/10 —(2)
Solving equation (1) and (2) , we get m=11/400 and w=1/400
Amount of work 10 women can do in a day = 10 × (1/400) = 1/40
Ie, 10 women can complete the work in 40 days
A. 10 days
B. 14 days
C. 15 days
D. 9 days
A. 10 min
B. 20 min
C. 30 min
D. 40 min
A. 15 days
B. 14 days
C. 16 days
D. 30 days
Raio of times taken by A and B = 1 : 3
If the difference of time is 2 days, B takes 3 days. If the difference of time is 10 days.
B takes [3/2×10]=15 days
