A cuboidal water tank contains 216 liters is water. Its depth is 1/3 of its length and breadth is ½ of 1/3 of the difference between length and depth. The length of the tank?
A. 2dm
B. 6dm
C. 18dm
D. 72dm
A. 2dm
B. 6dm
C. 18dm
D. 72dm
A. 7
B. 6
C. 3
D. 4
E. None of these
Explanation:
Investments of X, Y and Z respectively are Rs. 20000, Rs. 25000 and Rs. 30000
Let investment period of Z be x months.
Ratio of annual investments of X, Y and Z is (20000 * 12) : (25000 * 12) : (30000 * x)
= 240 : 300 : 30x = 8 : 10 : x
The of Z in the annual profit of Rs. 50000 is Rs. 14000.
=> [x/ (18 + x)] 50000 = 14000 => [x/ (18 + x)] 25 = 7
=> 25x = 7x + (18 * 7) => x = 7 months.
Z joined the business after (12 – 7) months. i.e., 5 months.
A. Rs 100000
B. Rs 11000
C. Rs 120000
D. Rs 170000
Explanation:
Let the sum be Rs x.
Then S. I = Rs (x × 8/100 × 2) = Rs 4x/25
C. I = Rs [x × (1 + 8/100)2 – x]
= Rs (x × 27/25 × 27/25 – x)
=Rs 104x/625 (C.I) – (S.I)
= Rs(104x/625 – 4x /25)
= Rs 4x /625
Therefore 4x/625 = 768
=> x = ((768 ×625)/4) = 120000
Therefore sum = Rs 120000
A. No change
B. 5 % decrease
C. 4 % increase
D. 4 % decrease
Let tax = Rs. 100 and consumption = 100 units
Original Expenditure = Rs. (100 × 100) = Rs. 10000
New Expenditure = Rs. (120 × 80) = Rs. 9600
Decrease in expenditure = (400/10000 x 100) % = 4 %
A. 8/15
B. 7/15
C. 11/15
D. 2/11
Amount of work P can do in 1 day = 1/15
Amount of work Q can do in 1 day = 1/20
Amount of work P and Q can do in 1 day = 1/15 + 1/20 = 7/60
Amount of work P and Q can together do in 4 days = 4 × (7/60) = 7/15
Fraction of work left = 1 – 7/15= 8/15
A. 1200 m²
B. 1500 m²
C. 12000 m²
D. 15000 m²
Actual length
= 30*500 cm Actual breadth
= 20*500 cm Actual area
= 30*20*500*500 = 15000 m²
A. 6
B. 12
C. 18
D. None of these
Let the numbers be 3x, 4x and 6x.
Then, 3x x 4x x 6x = 1944 72×3 = 1944
x3 = 27 ,=> x = 3
∴ Largest number = 6x = 18,