A can complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km / hr and second half at the rate of 24 km / hr. Find the total journey in km.
		A. 220 km
B. 224 km
C. 230 km
D. 234 km
		A. 220 km
B. 224 km
C. 230 km
D. 234 km
		A. 35, 25 kmph
B. 80, 40 kmph
C. 40, 60 kmph
D. 50, 55 kmph
Explanation:
Speed downstream = 60 + 20 = 80 kmph
Speed upstream = 60 – 20 = 40 kmph
		A. 60
B. 70
C. 80
D. 90
E. None of these
Explanation:
Given, 40% of Ram’s marks = 20% of Rahim’s marks = 30% of Robert’s marks.
Given, marks of Robert = 80
30% of 80 = 30/100 * 8 = 24
Given, 40% of Ram’s marks = 24.
=> Ram’s marks = (24 * 100)/40 = 60
Also, 20% of Rahim’s marks = 24
=> Rahim’s marks = (24 * 100)/20 = 120
Average marks of Ram and Rahim = (60 + 120)/2 = 90.
		A. 4800
B. 5760
C. 2880
D. 15000
Explanation:
Treat all boys as one unit. Now there are four students and they can be arranged in 4! ways. Again five boys can be arranged among themselves in 5! ways.
Required number of arrangements = 4! * 5! = 24 * 120 = 2880.
		A. 6
B. 5
C. 10
D. 7
Explanation:
The number of shirts = X
 Rebate = (25/100 × 32 X) = 8X
 8X = 40 or X = 5
		A. 12 min
B. 14 min
C. 16 min
D. 20 min
In this problem, rate of water pipe (waste) is more, the tank will be emptied when the pipes are opened.
Work done in total emptying in 1 min.
=1/16−1/32=1/32
Now, full tank will be emptied by them in 32 minutes.
Half full tank will be emptied in 16 minutes.
		A. Rs. 9000.30
B. Rs. 9720
C. Rs. 10123.20
D. Rs. 10483.20
Explanation:
Amount = [25000 * (1 + 12/100)3]
= 25000 * 28/25 * 28/25 * 28/25 = Rs. 35123.20
C.I. = (35123.20 – 25000) = Rs. 10123.20