The diameters of two spheres are in the ratio 1:2 what is the ratio of their volumes?
The diameters of two spheres are in the ratio 1:2 what is the ratio of their volumes?
A. 3:4
B. 9:16
C. 1:8
D. 4:3
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Find the amount on Rs.8000 in 9 months at 20% per annum, if the interest being compounded quarterly?
Find the amount on Rs.8000 in 9 months at 20% per annum, if the interest being compounded quarterly?A. Rs.1261
B. Rs.9261
C. Rs.9621
D. Rs.9162
Explanation:
A = 8000(21/20)3 = 9261Atif and Bilal, 110 km apart, start cycling towards each other. If Atif covers a distance of 6 km to Bilal’s 5 km, how far will Atif have travelled when they meet?
Atif and Bilal, 110 km apart, start cycling towards each other. If Atif covers a distance of 6 km to Bilal’s 5 km, how far will Atif have travelled when they meet?A. 66 km
B. 55 km
C. 50 km
D. 60 kmAn automobile financier claims to be lending money at simple interest, but he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of interest becomes :_________?
An automobile financier claims to be lending money at simple interest, but he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of interest becomes :_________?A. 10%
B. 10.25%
C. 10.50%
D. None of these
Let the sum be Rs. 100. Then, S.I. for first 6 months = Rs. ( 100 X 10 X 1/100 X 2 ) = Rs. 5. S.I. for last 6 months = Rs. ( 105 X 10 X 1/100 X 2 ) = Rs. 5.25. So, amount at the end of 1 year=Rs.(100 + 5 + 5.25) = Rs. 110.25 Effective rate = (110.25 – 100) = 10.25%.Assume that 20 cows and 40 goats can be kept for 10 days for Rs.460. If the cost of keeping 5 goats is the same as the cost of keeping 1 cow, what will be the cost for keeping 50 cows and 30 goats for 12 days?
Assume that 20 cows and 40 goats can be kept for 10 days for Rs.460. If the cost of keeg 5 goats is the same as the cost of keeg 1 cow, what will be the cost for keeg 50 cows and 30 goats for 12 days?A. Rs.1104
B. Rs.1000
C. Rs.934
D. Rs.1210
Assume that cost of keeg a cow for 1 day = c ,
cost of keeg a goat for 1 day = g
Cost of keeg 20 cows and 40 goats for 10 days = 460
Cost of keeg 20 cows and 40 goats for 1 day = 460/10 = 46
=> 20c + 40g = 46
=> 10c + 20g = 23 —(1)
Given that 5g = c
Hence equation (1) can be written as 10c + 4c = 23 => 14c =23
=> c=23/14
cost of keeg 50 cows and 30 goats for 1 day
= 50c + 30g
= 50c + 6c (substituted 5g = c)
= 56 c = 56×23/14
= 92
Cost of keeg 50 cows and 30 goats for 12 days = 12×92 = 1104P can lay railway track between two stations in 16 days. Q can do the same job in 12 days. With the help of R, they completes the job in 4 days. How much days does it take for R alone to complete the work?
P can lay railway track between two stations in 16 days. Q can do the same job in 12 days. With the help of R, they completes the job in 4 days. How much days does it take for R alone to complete the work?A. 9(3/5) days
B. 9(1/5) days
C. 9(2/5) days
D. 10 days
Amount of work P can do in 1 day = 1/16
Amount of work Q can do in 1 day = 1/12
Amount of work P, Q and R can together do in 1 day = 1/4
Amount of work R can do in 1 day = 1/4 – (1/16 + 1/12) = 3/16 – 1/12 = 5/48
=> Hence R can do the job on 48/5 days = 9 (3/5) daysI bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss?
I bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss?A. Rs.28
B. Rs.280
C. Rs.140
D. Rs.70
Explanation:
x*(85/100) = (480 – x)119/100
x = 280