A. 80%
B. 85%
C. 96%
D. 125%
I II III
120 125 100
125———-120
100———–? => 96%
A. 4800
B. 5760
C. 2880
D. 15000
Explanation:
Treat all boys as one unit. Now there are four students and they can be arranged in 4! ways. Again five boys can be arranged among themselves in 5! ways.
Required number of arrangements = 4! * 5! = 24 * 120 = 2880.
A. 1 : 2
B. 3 : 1
C. 2 : 1
D. 1 : 3
Explanation:
Let the speed of the boat in still water be 4 km/hr and speed of the current be u km/hr.
Rate downstream = (u + v) km/hr.
Rate upstream = (u- v)km/hr
Let the distance covered in each case be x km.
Then 2x/(u + v) = x / (u – v)
=> 2 (u – v) = ( u + v)
=> u =3v
=> u/v =3/1
A. 15500Sq.m
B. 15400Sq.m
C. 15200Sq.m
D. 15300Sq.m
A. 48
B. 34(2/7)
C. 44
D. 45
(1/A)+(1/B) = (1/20) (1/B)+(1/C) = (1/30) (1/A)+(1/C) = (1/40) Solving the three equations,
A=48
A. 750
B. 500
C. 250
D. 125
Explanation:
Let x% candidates take both the subjects.
Therefore, Percentage of candidates who opted physics = 65.8%
And percentage of candidates who opted mathematics = 59.2%
Therefore, x =(65.8 + 59.2 – 100)%
= (125 -100)% = 25%
Also total number of candidates = 2000
Therefore, Number of candidates who opted both the subjects = 25/100 x 2000 =500
A. 4.5 kmph
B. 4.8 kmph
C. 5 kmph
D. 5.1 kmph
Time taken for the forward journey
= 2/6 = (1/3) hrs Time taken for the return journey
= 2/4 = (1/2) hrs Total time = 5/6 hrs Average speed = 4/(5/6) = 24/5 = 4.8kmph