The salary of Mr. X is 30% more than that of Mr. Y . Find what percent of Mr. Y’s salary is less than Mr. X’s?
		A. 30%
B. 25 1/13 %
C. 23 1/13 %
D. 22 1/13 %
y=100 x=130
130———30
100———? => 23 1/3%
		A. 30%
B. 25 1/13 %
C. 23 1/13 %
D. 22 1/13 %
y=100 x=130
130———30
100———? => 23 1/3%
		A. neither profit nor loss
B. 1%
C. 2%
D. 3%
Explanation:
Profit on first article = 20% of 1000 = 200.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
		A. 12 min
B. 15 min
C. 25 min
D. 50 min
Explanation:
Part filled by A in 1 min. = 1/20
Part filled by B in 1 min. = 1/30
part filled by (A + B) in 1 min. = 1/20 + 1/30 = 1/12.
Both the pipes can fill the tank in 12 minutes.
		A. 150
B. 140
C. 130
D. 110
Explanation:
(60/100) * X – 40 = 50
6X = 900
X = 150
		A. 36
B. 45
C. 48
D. 49
Explained with 5 Steps.
1.Data:
Speed 1 = 60 km/hr
Speed 2= 90 km/hr
Relative speed= (60+90)km/hr
Relative speed= 150 km/hr
Relative speed= 150×1000m/3600 Sec
Relative speed= 150,000m/3600 Sec
Relative speed= 1500m/36Sec
Relative speed= 42m/Sec
Distance 1= 1.10km
Distance 2= 0.9km
Total distance= (1.10+0.9) km
D(t)= 2 km => 2×1000m
D(t) = 2000m
2 Required:
Time=T=???
3. Formula:
S = V×T
For T
T= S/V
4. Solution:
Putting value in formulas.
T= 2000m/ 42 m/sec
T= 48Sec
5. Result:
Time =T= 48 Sec
		A. Rs.1104
B. Rs.1000
C. Rs.934
D. Rs.1210
Assume that cost of keeg a cow for 1 day = c ,
cost of keeg a goat for 1 day = g
Cost of keeg 20 cows and 40 goats for 10 days = 460
Cost of keeg 20 cows and 40 goats for 1 day = 460/10 = 46
=> 20c + 40g = 46
=> 10c + 20g = 23 —(1)
Given that 5g = c
Hence equation (1) can be written as 10c + 4c = 23 => 14c =23
=> c=23/14
cost of keeg 50 cows and 30 goats for 1 day
= 50c + 30g
= 50c + 6c (substituted 5g = c)
= 56 c = 56×23/14
= 92
Cost of keeg 50 cows and 30 goats for 12 days = 12×92 = 1104
		A. 216
B. 217.50
C. 236.50
D. 245
Explanation:
Given expression = (45/100 * 750) – (25/100 * 480) = (337.50 – 120) = 217.50