2, 6, 12, 20, 30, 42, 56, (….)
2, 6, 12, 20, 30, 42, 56, (….)
[A].
[B].
[C].
[D].
Answer: Option C
Explanation:
The pattern is 1 x 2, 2 x 3, 3 x 4, 4 x 5, 5 x 6, 6 x 7, 7 x 8.
So, the next number is 8 x 9 = 72.
[B].
[C].
[D].
Answer: Option C
Explanation:
The pattern is 1 x 2, 2 x 3, 3 x 4, 4 x 5, 5 x 6, 6 x 7, 7 x 8.
So, the next number is 8 x 9 = 72.
[B].
[C].
[D].
Answer: Option C
Explanation:
| Required number of ways | = (8C5 x 10C6) | |||||||
| = (8C3 x 10C4) | ||||||||
| 
 | ||||||||
| = 11760. | 
[B].
[C].
[D].
Answer: Option D
Explanation:
We need to know the S.I., principal and time to find the rate.
Since the principal is not given, so data is inadequate.
		A. 4.25 kmph
B. 6 kmph
C. 6.5 kmph
D. 8.5 kmph
[B].
[C].
[D].
Answer: Option A
Explanation:
By hit and trial, we find that
47619 x 7 = 333333.
		A. 1 : 2
B. 3 : 1
C. 2 : 1
D. 1 : 3
Explanation:
Let the speed of the boat in still water be 4 km/hr and speed of the current be u km/hr.
Rate downstream = (u + v) km/hr.
Rate upstream = (u- v)km/hr
Let the distance covered in each case be x km.
Then 2x/(u + v) = x / (u – v)
=> 2 (u – v) = ( u + v)
=> u =3v
=> u/v =3/1
[B].
[C].
[D].
Answer: Option B
Explanation:
P.W. = Rs. (540 – 90) = Rs. 450.
S.I. on Rs. 450 = Rs. 90.
| S.I. on Rs. 540 = Rs. | 90 | x 540 | = Rs. 108. | ||
| 450 | 
B.D. = Rs. 108.