A. 300
B. 200
C. 400
D. 500
Explanation:
(60/100) * X + 120 = X
2X = 600
X = 300
A. 85
B. 89
C. 54
D. 91
A. 3 hrs.
B. 4 hrs,
C. 5 hrs.
D. 6 hrs.
X’s 1 hour work = 1/10
Y’s 1 hour work = 1/15
(x+y)’s 1 hour work = 1/10+1/15=5/30=1/6
Both the taps can fill the tank in 6 hrs.
A. 2040
B. 2010
C. 135
D. 150
A. 120
B. 80
C. 192
D. 48
If A invests amount C1 for T1 time and his of profit is P1, and B invests amount C2 for T2 time and his of profit is P2, then, C1 * T1 / C2 * T2 = P1/P2
If P is the Nasir’s of profit, then Changaz gets (240 – P)
Therefore, 6000 * 12 / 3000 * 6 = (240 – P) / P = 72/ 18 = 4
4P = (240 – P)
5P = 240
P = 48
A. 35%
B. 30%
C. 40%
D. 42 6/7%
Explanation:
SP = CP + g
50 SP = 50 CP + 15 SP
35 SP = 50 CP
35 — 15 CP gain
100 — ? => 42 6/7%
A. 9:1
B. 4:7
C. 7:1
D. 2:5
Explanation:
Milk = 3/5 * 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 – 6 = 6 liters
Remaining water = 8 – 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10 = 8 liters.
Amount of water removed = 2 liters.
Remaining milk = (16 – 8) = 8 liters.
Remaining water = (4 -2) = 2 liters.
The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.