[B].
[C].
[D].
Answer: Option B
Explanation:
When n is odd, (xn + an) is always divisible by (x + a).
Each one of (4743 + 4343) and (4747 + 4347) is divisible by (47 + 43).
A. Rs. 3096
B. Rs. 4076
C. Rs. 4085
D. Rs. 4096
Explanation:
Principal = [4913 / (1 + 25/(4 * 100))3]
= 4913 * 16/17 * 16/17 * 16/17 = Rs. 4096.
A. Rs 50
B. Rs 60
C. Rs 61
D. Rs 600
Explanation:
S.I = Rs(8000 × 5/100 ×3) = Rs 1200
C.I = Rs [8000 × (1+5/100)3– 8000
= Rs [(8000 × 21/20×21/20×21/20)-8000]
=Rs (9261-8000)=Rs 1261
(c.I)-(S.I) = Rs (1261 – 1200) = Rs61.
[B].
[C].
[D].
Answer: Option D
Explanation:
We have: (l – b) = 23 and 2(l + b) = 206 or (l + b) = 103.
Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) m2 = 2520 m2.
A. 3
B. 7.5
C. 2.25
D. 1.5
Explanation:
M = 4.5
S = x
DS = 4.5 + x
US = 4.5 + x
4.5 + x = (4.5 – x)2
4.5 + x = 9 -2x
3x = 4.5
x = 1.5
A. 7 years
B. 10 years
C. 15 years
D. 20 years
Explanation:
Let principal be Rs x and the rate is R % p.a.
Then X × (1 + R/100)5 = 2x
=> (1 + R/100)5 = 2
Let x × (1 + R/100)t = 8x
=> (1 + R/100)t = 8 = 23
={(1 + R/100)5 }3
=> (1 + R/100)t = (1 + R/100)15
=> T = 15 Years
[B].
[C].
[D].
Answer: Option A
Explanation:
Let AB be the tree and AC be its shadow.
Let ACB = .
| Then, | AC | = | 3 cot = 3 |
| AB |
= 30°.