What is the total surface area of a right circular cone of height 14 cm and base radius 7 cm?
A. 344.35 cm2
B. 344.35 cm2
C. 344.35 cm2
D. None of these
A. 344.35 cm2
B. 344.35 cm2
C. 344.35 cm2
D. None of these
A. 9:1
B. 4:7
C. 7:1
D. 2:5
Explanation:
Milk = 3/5 * 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 – 6 = 6 liters
Remaining water = 8 – 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10 = 8 liters.
Amount of water removed = 2 liters.
Remaining milk = (16 – 8) = 8 liters.
Remaining water = (4 -2) = 2 liters.
The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
A. 12:00 pm
B. 2:00 am
C. 12:00 am
D. 10:00 pm
Jameel works for 5 hours. So he completes 5/15 = 1/3 of the task Nasir has to complete 2/3rd of the task 12*2/3 = 8 hours are needed. He completes the task at 12:00 am.
A. 8
B. 10
C. 12
D. Cannot be determined
A. 7 liters
B. 15 liters
C. 10 liters
D. 9 liters
Explanation:
Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters.
A. Rs. 12
B. Rs. 12.96
C. Rs. 14.40
D. None of these
Explanation:
90 : 10.80 :: 120 : x
X = (10.80 ×120)/90 = 14.40
Hence, the toy must be sold for Rs. 14.40