As we know about BODMAS rule i.e brackets of division multiplication addition subtraction.
{ 2 +[ (2/2) *2] } -2
{ 2 +[ 1*2] } -2
{ 2 +[ 2] } -2
{ 4 } -2. So answer is 2.
A. 7
B. 8
C. 9
D. 6
Let P takes x days to complete the work
Then Q takes x/2 days and R takes x/3 days to finish the work
Amount of work P does in 1 day = 1/x
Amount of work Q does in 1 day = 2/x
Amount of work R does in 1 day = 3/x
Amount of work P,Q and R do in 1 day = 1/x + 2/x + 3/x = 1/x (1 + 2 + 3) = 6/x
6/x = 2
=> x = 12
=> Q takes 12/2 days = 6 days to complete the work
A. 46
B. 56
C. 34
D. 57
Explanation:
1 to 11 = 11 * 50 = 550
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6th = 294 + 312 – 550 = 56
A. 1500
B. 1800
C. 2100
D. 1950
P = 15(100/10)2 => P = 1500
A. 9cm
B. 10cm
C. 11cm
D. 12cm
Explanation:
Ratio of sides = ½ : 1/3 : ¼ = 6: 4 : 3
Side are (32 x 6/13)cm, (32 x 4/13)cm and (52 x 3/13)cm i.e…, 24 cm , 16 cm, 12 cm.
Length of smallest side = 12 cm
A. Rs. 13.50
B. Rs. 14.50
C. Rs. 15.50
D. Rs. 16.50
E. None of these
Explanation:
Let the quantities of A and B mixed be 3x kg and 7x kg.
Cost of 3x kg of A = 9(3x) = Rs. 27x
Cost of 7x kg of B = 15(7x) = Rs. 105x
Cost of 10x kg of the mixture = 27x + 105x = Rs. 132x
Cost of 5 kg of the mixture = 132x/10x (5) = Rs. 66
Profit made in selling 5 kg of the mixture = 25/100 (cost of 5 kg of the mixture) = 25/100 * 66 = Rs. 16.50
A. 2 men
B. 12 men
C. 9 men
D. 18 men
For the work to be completed in 9 days,
6 men are required. Time and men are inversely proportional. For the work to be completed in 3 days,
6*9/3 = 18 men are required