Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

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Question: Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
[A].

9

[B].

11

[C].

13

[D].

15

Answer: Option D

Explanation:

Let the three integers be x, x + 2 and x + 4.

Then, 3x = 2(x + 4) + 3      x = 11.

Third integer = x + 4 = 15.

Video Explanation: https://youtu.be/_77C9YE321Y