Question: Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
[A].9
11
13
15
[A].
[B].
[C].
[D].
Answer: Option D
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y