The surface of a cube is 24sq cm. Find its volume?
The surface of a cube is 24sq cm. Find its volume?
A. 8 cc
B. 16 cc
C. 32 cc
D. 64 cc
6a2 = 24
a = 2 => a3 = 8cc
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A completes 80% of a work in 20 days. Then B also joins and A and B together finish the remaining work in 3 days. How long does it need for B if he alone completes the work?
A completes 80% of a work in 20 days. Then B also joins and A and B together finish the remaining work in 3 days. How long does it need for B if he alone completes the work?A. 37 ½ days
B. 22 days
C. 31 days
D. 22 days
Work done by A in 20 days = 80/100 = 8/10 = 4/5
Work done by A in 1 day = (4/5) / 20 = 4/100 = 1/25 — (1)
Work done by A and B in 3 days = 20/100 = 1/5 (Because remaining 20% is done in 3 days by A and B)
Work done by A and B in 1 day = 1/15 —(2)
Work done by B in 1 day = 1/15 – 1/25 = 2/75
=> B can complete the work in 75/2 days = 37 ½ daysA car travels 50% faster than a bike. Both start at the same time from A to B. The car reaches 25 minutes earlier than the bike. If the distance from A to B is 100 km, find the speed of the bike.
A car travels 50% faster than a bike. Both start at the same time from A to B. The car reaches 25 minutes earlier than the bike. If the distance from A to B is 100 km, find the speed of the bike.A. 120 km
B. 100 km
C. 80 km
D. 75 km
Let the speed of the bike be x kmph. Then the speed of the car will be 3x/2 kmph. Time taken by the bike
t1 = 100/x Time taken by the bike
t2 = 100/(3x/2) t1 – t2 = 25/60 (100/x) – (100/(3x/2)) = 5/12 Solving the equation, x = 80 kmphMahad marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 496.80?
Mahad marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 496.80?A. 18%
B. 21%
C. 20%
D. 19%
E. None of these
Explanation:
CP = Rs. 540, MP = 540 + 15% of 540 = Rs. 621
SP = Rs. 496.80, Discount = 621 – 496.80 = 124.20
Discount % = 124.2/621 * 100 = 20%The length of a rectangular plot is increased by 25%. To keep it’s area uncharged the width of the plot should be___________?
The length of a rectangular plot is increased by 25%. To keep it’s area uncharged the width of the plot should be___________?A. Kept unchanged
B. Increased by 25%
C. Increased by 20%
D. Reduced by 20%Explanation:
Let the length be x metres and breadth be y metres
Then it’s area =(xy)m2
New length =(125/100 x)m =(5x/4)m.
Let the new breadth be 2 metres
Then xy 5x/4 x 2 => 2 = 4/5 y
Decreased in width =(y -4/5 y) = y/5 metres
Decreased % in width =(y/5 x 1/y x 100)% = 20%Find the fourth proportion to 3, 7 and 9.
Find the fourth proportion to 3, 7 and 9.A. 63
B. 31
C. 21
D. 27
3:7::9:x 3x=7*9=63 x=21An amount of 5,000 is invested at a fixed rate of 8 per cent per annum. What amount will be the value of the investment in five years time, if the interest is compounded every six months?
An amount of 5,000 is invested at a fixed rate of 8 per cent per annum. What amount will be the value of the investment in five years time, if the interest is compounded every six months?A. 7401.22
B. 3456
C. 4567
D. 7890