A. 18
B. 12
C. 9
D. 6
A. 3:2
B. 1:2
C. 1:5
D. 2:1
p = q+(50/100)q = 1.5q p:q = 1.5q:q = 1.5:1 = 3:2
A. 485
B. 431
C. 391
D. 381
Explanation:
HCF of 323, 437 = 19
323 * 437 = 19 * 19 * x
x = 391
A. 48
B. 42
C. 60
D. 70
7x+8x=90 15x=90 x=6 Number of boys=7x=42
A. 5/21
B. 5/14
C. 9/14
D. 16/21
Explanation:
Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)
As remaining person can be any one among three couples left.
Required probability = (⁵C₂ * ⁶C₁)/¹⁰C₅
= (10 * 6)/252 = 5/21
A. 20.98% profit
B. 20.98% loss
C. 20.89% profit
D. 20.89% loss
A. Rs. 2000
B. Rs. 2200
C. Rs. 2400
D. None of these
Explanation:
Let C.P. be Rs. x.
Then, (1920 – x)/x * 100 = (x – 1280)/x * 100
1920 – x = x – 1280
2x = 3200 => x = 1600
Required S.P. = 125 % of Rs. 1600 = 125/100 * 1600 = Rs. 2000.