The sum of first 45 natural numbers is:
The sum of first 45 natural numbers is:
[A].
[B].
[C].
[D].
Answer: Option A
Explanation:
Let Sn = (1 + 2 + 3 + … + 45)
This is an A.P. in which a = 1, d = 1, n = 45 and l = 45
| Sn = | n | (a + l) | = | 45 | x (1 + 45) = (45 x 23) = 1035 | 
| 2 | 2 | 
Required sum = 1035.
