A. 52.65
B. 56.25
C. 50.75
D. 42.75
A. 237.55
B. 337
C. 443
D. 334
Cash price = $3695
Deposit =1/3 of $3695
= $1231.67
Loan amount = $3695.00 − $1231.67
= $2463.33
Total cost of loan = $25.97 × 104
= $2700.88
Interest charged = total amount − loan
I = A − P
= 2700.88 − 2463.33
= 237.55
A. 160
B. 175
C. 180
D. 195
A. Rs. 3500
B. Rs. 4000
C. Rs. 4500
D. Rs. 5000
Let salary be Rs. x.
Then, x – 15 % of x – 30 % of 85 % of x = 2380
or x – 15x/100 – (30×85×x)/(100×100) = 2380
or 200 x – 30 x – 51 x = 2380 X 200
or 119 x = 2380 X 200
or x = (2380×200)/119 = 4000
A. 1 : 3
B. 1 : 4
C. 2 : 3
D. Data inadequate
Let the principal be P and rate of interest be R%. So Required ratio = [(P x R x 6/100) / (13 x R x 9/100)] = 6PR/9PR = 6/9 = 2 : 3
A. Rs.4400
B. Rs.4445
C. Rs.4460
D. Rs.4520
Explanation:
Sum be P
P(1 + R/100)3 = 6690 – (i)
P(1 + R/100)2 = 10, 035 – (ii)
By dividing (i) and (ii)
(1 + R/100)3 = 10035/6690 = 3/2
Therefore, P = (6690 x 2/3) = Rs. 4460
A. 15
B. 10
C. 14
D. 12