The side of a rhombus is 26 m and length of one of its diagonals is 20 m. The area of the rhombus is_______?
A. 529 sq m
B. 240 sq m
C. 260 sq m
D. 480 sq m
Explanation:
262 – 102 = 242
d1 = 20 d2 = 48
1/2 * 20 * 48 = 480
A. 529 sq m
B. 240 sq m
C. 260 sq m
D. 480 sq m
Explanation:
262 – 102 = 242
d1 = 20 d2 = 48
1/2 * 20 * 48 = 480
A. Rs. 45
B. Rs. 50
C. Rs. 55
D. Rs. 60
A. -21
B. 1
C. 61
D. 21
Explanation:
a2 + b2 + ab = a2 + b2 + 2ab – ab
i.e., (a + b)2 – ab
from x2 – 9x + 20 = 0, we have
a + b = 9 and ab = 20. Hence the value of required expression (9)2 – 20 = 61.
A. 485
B. 431
C. 391
D. 381
Explanation:
HCF of 323, 437 = 19
323 * 437 = 19 * 19 * x
x = 391
A. Rs.250
B. Rs.225
C. Rs.275
D. Rs.200
Explanation:
CP1 = 100 SP1 = 90
CP2 = 80 SP2 = 80 * (140/100) = 112
22 —– 100
55 —– ? => Rs.250
A. 19/52
B. 17/52
C. 5/13
D. 4/13
Explanation:
P(SᴜK) = P(S) + P(K) – P(S∩K), where S denotes spade and K denotes king.
P(SᴜK) = 13/52 + 4/52 – 1/52 = 4/13
A. 6 1/8
B. 5 3/4
C. 6 3/4
D. 5 7/8
Explanation:
6 of 5/8 / 5/8 – 1/8
30/8 * 8/5 – 1/8 = 6 – 1/8 = 5 7/8