The rational number for recurring decimal 0.125125…. is:
The rational number for recurring decimal 0.125125…. is:
[A].
| 63 |
| 487 |
[B].
| 119 |
| 993 |
[C].
| 125 |
| 999 |
[D].
Answer: Option C
Explanation:
| 0.125125… = 0.125 = | 125 |
| 999 |
| 63 |
| 487 |
[B].
| 119 |
| 993 |
[C].
| 125 |
| 999 |
[D].
Answer: Option C
Explanation:
| 0.125125… = 0.125 = | 125 |
| 999 |
[B].
[C].
[D].
Answer: Option D
Explanation:
99 = 11 x 9, where 11 and 9 are co-prime.
By hit and trial, we find that 114345 is divisibleby 11 as well as 9. So, it is divisible by 99.
[B].
| 1 |
| 40 |
[C].
[D].
Answer: Option C
Explanation:
Let the required number of days be x.
Less cows, More days (Indirect Proportion)
Less bags, Less days (Direct Proportion)
| Cows | 1 | : | 40 | :: 40 : x | |
| Bags | 40 | : | 1 |
1 x 40 x x = 40 x 1 x 40
x = 40.
A. 35, 25 kmph
B. 80, 40 kmph
C. 40, 60 kmph
D. 50, 55 kmph
Explanation:
Speed downstream = 60 + 20 = 80 kmph
Speed upstream = 60 – 20 = 40 kmph
[B].
[C].
[D].
Answer: Option B
Explanation:
Clearly, l = (48 – 16)m = 32 m,
b = (36 -16)m = 20 m,
h = 8 m.
Volume of the box = (32 x 20 x 8) m3 = 5120 m3.
[B].
[C].
[D].
Answer: Option B
Explanation:
639 is not divisible by 7
2079 is divisible by each of 3, 7, 9, 11.
A. Rs. 2.50
B. Rs. 3
C. Rs. 3.75
D. Rs. 4