The product of two numbers is 2025 and their HCF is 15 their LCM is____________?
A. 2040
B. 2010
C. 135
D. 150
A. 2040
B. 2010
C. 135
D. 150
A. 55606
B. 55697
C. 55967
D. 73373
Explanation:
64309 – 8703 + 798 – 437 => 65107 – 9140 = 55967
A. 383
B. 372
C. 380
D. 374
Explanation:
? = 183.21 + 200 = 383
A. 625
B. 630
C. 640
D. 650
Explanation:
Let the sum be Rs. x. Then,
[x (1 + 4/100)2 – x] = (676/625 x – x) = 51/625 x
S.I. = (x * 4 * 2)/100 = 2x/25
51x/625 – 2x/25 = 1 or x = 625.
A. 75
B. 81
C. 85
D. 89
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F of 551 and 1073 = 29;
First number = 551/29 = 19
Third number = 1073/29 = 37.
Required sum = 19 + 29 + 37 = 85.
A. 2 : 5
B. 3 : 7
C. 5 : 3
D. 7 : 3
A. 0.0024
B. 0.024
C. 0.24
D. 0.00024
Explanation:
24 – [2.4 – {0.24 * 2 – (0.024 – ?)}] = 22.0584
24 – [2.4 – {0.48 – (0.024 – ?)}] = 22.0584
24 – [2.4 – 0.48 + 0.024 – ?] = 22.0584
24 – 2.4 + 0.48 – 0.024 + ? = 22.0584
? = 22.0584 – 24.48 + 2.424
? = 24.2824 – 24.48 => ? = 0.0024