The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

Question:
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

[A].

504

[B].

536

[C].

544

[D].

548

Answer: Option D

Explanation:

Required number = (L.C.M. of 12, 15, 20, 54) + 8

   = 540 + 8

   = 548.